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Alina [70]
3 years ago
5

What is the standard form of the equation of the circle?

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
4 0
The standard form of the equation of a circle is:
(x - a) {}^{2}  + (y - b) {}^{2}  = r {}^{2}
Where the point (a,b) represents the centre and r is the radius. So, given your information, the equation will be:
{(x + 4)}^{2}  +  {(y + 3)}^{2}  = 25
Dafna1 [17]3 years ago
4 0
(x – h)2<span> + (y – k)</span>2<span> = r</span><span>2 would be the equation </span>
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Translate the sentence into an equation.
nekit [7.7K]

Answer:

6c - 7 = 5

Step-by-step explanation:

following the steps in the sentence.

because it is 7 less you have a subtraction problem ( -7)

because it is 6 and a number you have a multiplication problem (6c)

it equals 5 (=5)

8 0
2 years ago
Let a, b, and c be constants, and let x be a variable. Which of the following is
Nonamiya [84]

Answer:

C

Step-by-step explanation:

We have:

a(x+b)

Where a<0.

We would like to solve for a. So, let’s divide both sides by a.

Notice that a<0. Therefore, a is negative. Hence, we must flip the sign since we are dividing by a negative. This yields:

x+b>\frac{c}{a}

Now, we will subtract b from both sides. Therefore, our inequality is:

x>\frac{c}{a}-b

Hence, our answer is C.

5 0
2 years ago
The standard form of the equation through the points (0,5) and (-2, -1) is?
In-s [12.5K]
Answer: y = 3x + 5

Look at graph:

4 0
2 years ago
What is the solution to the equation below?<br> 8-(x+10)=2x-1
dangina [55]
X = - 1/3 or an alternate form x = -0.3, x = -3 to the power of -1
6 0
2 years ago
Read 2 more answers
Consider the case of a triangle with sides 5, 12, and the angle between them 90°.
Daniel [21]

Answer:

a) Applying Pithagoras Theorem

b) Trigonometric relations

c) No we can not

d) No we can not

e) See step-by-step explanation

f) See step-by-step-explanation

Step-by-step explanation:

a) The easiest method for calculating the missing side is applying Pithagoras Theorem

c²  =  a²  +  b²

c²  =  (5)²  +  (12)²      ⇒  c²  = 25 + 144    ⇒ c²  =  169    ⇒  c  = 13

b) The easiest method to find the missing angles, is to calculate the sin∠ and then look for arcsin fuction in tables.

sin ∠α = 5/13    sin ∠α = 0.3846    ⇒      arcsin (0.3846 )   α  = 23⁰

Now we can either get the other angle subtracting 180 - 90 - 23 = 67⁰

Or calculating sinβ = 12 /13    sinβ = 0.9230  arcsin(0.9230)   β = 67⁰

c) The law of cosines should not be applied to right triangles, in fact for instance in our particular case we have:

Question a)

c²  = a² + b² - 2*a*b*cos90⁰   (law of cosines ) but cos 90⁰ = 0

then c²  = a² + b² which is the expression for theorem of Pithagoras

In case you look for calculating the missing angles

c²  = a²  +  b²  - 2*5*13*cos α

169 = 25  +  144 - 2*5*13* cos α

As you can see 169 - 25 - 144 = 0

Then we can not  apply law of cosine in right triangles, we shoul apply trigonometric relations and Pithagoras theorem, and as we saw you can get the expression of Pithagoras theorem from cosine law

c²  =  a²  +  b²  - 2*a*b*cos∠90°    cos ∠ 90°  = 0

Then     c²  =  a²  +  b²

3 0
3 years ago
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