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Alina [70]
3 years ago
5

What is the standard form of the equation of the circle?

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
4 0
The standard form of the equation of a circle is:
(x - a) {}^{2}  + (y - b) {}^{2}  = r {}^{2}
Where the point (a,b) represents the centre and r is the radius. So, given your information, the equation will be:
{(x + 4)}^{2}  +  {(y + 3)}^{2}  = 25
Dafna1 [17]3 years ago
4 0
(x – h)2<span> + (y – k)</span>2<span> = r</span><span>2 would be the equation </span>
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the area of a rectangular back yard is given by the trinomial b^2+5b-24. What are possible dimensions of the backyard?
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B^2+5b-24 Using the AC method for factoring (b+8)(b-3)
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2 years ago
A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo
djverab [1.8K]

Answer:

a) y(t)=50000-49990e^{\frac{-2t}{25}}

b) 31690.7 g/L

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is \frac{dy}{dt}=R_{i}-R_{o}, where R_{i} is the rate of salt entering and R_{o} is the rate of salt going outside.

Then we have, R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}, and

R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}

So we obtain.  \frac{dy}{dt}=4000-\frac{2y}{25}, then

\frac{dy}{dt}+\frac{2y}{25}=4000, and using the integrating factor e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}, therefore  (\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}, we get   \frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}, after integrating both sides y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C, therefore y(t)= 50000 +Ce^{\frac{-2t}{25}}, to find C we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions y(0)=10, so 10= 50000+Ce^{\frac{-0*2}{25}}

10=50000+C\\C=10-50000=-49990

Finally we can write an expression for the amount of salt in the tank at any time t, it is y(t)=50000-49990e^{\frac{-2t}{25}}

b) The tank will overflow due Rin>Rout, at a rate of 80 L/min-40L/min=40L/min, due we have 500 L to overflow \frac{500L}{40L/min} =\frac{25}{2} min=t, so we can evualuate the expression of a) y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7, is the salt concentration when the tank overflows

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3 years ago
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42 rhhrhjejrjfitkkrjrjrhrt
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Find the equation of the exponential function represented by the table below: y 0 0.01 1 0.005 2 0.0025 3 0.00125 Submit Answer
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