1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
antoniya [11.8K]
4 years ago
13

To determine whether or not they have a certain desease, 100 people are to have their blood tested. However, rather than testing

each individual separately, it has been decided first to group the people in groups of 10. The blood samples of the 10 people in each group will be pooled and analized together. If the test is negative. one test will suffice for the 10 people (we are assuming that the pooled test will be positive if and only if at least one person in the pool has the desease); whereas, if the test is positive each of the 10 people will also be individually tested and, in all, 11 tests will be made on this group. Assume the probability that a person has the desease is 0.05 for all people, independently of each other, and compute the expected number of tests necessary for each group.
Mathematics
1 answer:
matrenka [14]4 years ago
8 0

Answer: Expected number of tests = 5.013

Step-by-step explanation:

Define random variable X that marks the number of tests required for some certain

group. Observe that if the test is negative for all the people (which has probability 0.95), we make one and only one test. If some of the people is tested positive, we make ten additional tests for every person in that group separately. Hence, the expected number of tests will be for if they are all negative (1 test) and the case of at least one person testing positive (11 tests).

That Is,

E(X) = 1(0.95^10) + 11(1 - (0.95^10))

E(X) = 0.5987 + 4.414 = 5.013

You might be interested in
WILL GIVE BRAINLIEST!
expeople1 [14]

Answer:

Average\:Rate\:Change=-59.4

Step-by-step explanation:

The given function is f(x)=120(0.1)^x.


We want to find the average rate of change of this function from x=0 to x=2.


This is given by:

Average\:Rate\:Change=\frac{f(2)-f(0)}{2-0}


This implies that;


Average\:Rate\:Change=\frac{120(0.1)^2-120(0.1)^0}{2-0}


Average\:Rate\:Change=\frac{120(0.1)^2-120}{2}


Average\:Rate\:Change=\frac{120((0.1)^2-1)}{2}


Average\:Rate\:Change=\frac{60(0.01-1)}{1}


Average\:Rate\:Change=60(-0.99)


Average\:Rate\:Change=-59.4

5 0
3 years ago
Suppose the time that it takes a certain large bank to approve a home loan is Normally distributed with mean (in days) μ and sta
kolezko [41]

Answer:

(c) H0 should be rejected

Step-by-step explanation:

Null hypothesis (H0): population mean is equal to 5

Alternate hypothesis (Ha): population mean is greater than 5

Z = (sample mean - population mean) ÷ (sd/√n)

sample mean = 5.3, population mean = 5, sd = 1, n = 500

Z = (5.3 - 5) ÷ (1/√500) = 0.3 ÷ 0.045 = 6.67

Using the normal distribution table, for a one tailed test at 0.01 significance level, the critical value is 2.326

Conclusion:

Since 6.67 is greater than 2.326, reject the null hypothesis (H0)

4 0
3 years ago
Dan made 8 out of 10 free throws. What is the experimental probability that he will not make his next free throw? What is the th
nlexa [21]

Answer:

8/10--> 2/10 20 % scnahce of not makin git

Step-by-step explanation:

7 0
3 years ago
I need to find the answer to these questions in about 10 minutes or I'm screwed. please help me out.
Savatey [412]
For the first figure, the geometric figure used in the construction that is shown is the intersection of the angle bisectors of the triangle is the center of the inscribed circle.

For the second figure, the construction of the above figure in the circle represents how to find the intersection of the perpendicular bisectors of triangle ABC.

For the third figure, the statement that is demonstrated in the in line P intersecting line m perpendicularly is the set of points equidistant from the endpoints of  a line segment  is the perpendicular bisector of the segment.
7 0
4 years ago
Layla wrote a report on insects. She listed the lengths of a tiger beetles, carpenter ants, and aphids. The lengths were 1/2 inc
ahrayia [7]
First we would change the fractions into decimals and compare them. That way it would be easy to solve when needed.

1/2=0.50
5/8=0.625
1/8=0.125
   
Now we can see that 1/8 (0.125) is the smallest, followed by 1/2 (0.50), and 5/8 the largest. Now we can match the sizes with the insects.

Since the tiger beetle is the largest we will place that with the length of 5/8 since that is the largest.

The carpenter ant is second largest so it would be matched with 1/2

The aphid is the smallest so that would be with 1/8 as the smallest

*Hope that helped :D*
3 0
3 years ago
Other questions:
  • Which expression represents the sum (7z−15)+(8−6z)
    11·2 answers
  • 18 divided by 1919, how did you get your answer? Show your work!
    14·1 answer
  • 6. Jessie thinks that the first step in solving the equation shown below is to use the addition
    13·1 answer
  • 6^2 / (6^-2 * 5)^-2
    8·2 answers
  • Find two numbers between 3.456 and 3.457
    5·2 answers
  • What is 815 gal/hr blank qt/sec
    15·1 answer
  • The manufacturer that Russell works for makes
    15·1 answer
  • Factor the expression step by step : x^3 - x^2
    11·1 answer
  • Geocache box answers
    7·2 answers
  • Pls help me: A couple plans to have 4 children. The gender of each child is equally likely. Design a simulation involving 90 tri
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!