Radius of 8 find the area?

Name the property that the statement illustrates.

suter [353]

Answer:

Transitive property

Step-by-step explanation:

It statea that if a=b and b=c, then a=c.

7 0

3 years ago

I need ANSWERS for 13-14 please

inna [77]

13.

230 per hour. multiply 230 by the number of hours to find total posters.

The equation is Total = 230 x hours written as T = 230x, where x is the number of hours.

you have the total, so replace t with the value and solve for x:

1265 = 230x

Divide both sides by 230:

x = 1265 / 230

x = 5.5 hours.

14.

Mean is the average. To find the average, add the four scores together and divide by 4.

The expression is Mean = ( score 1 + score 2 + score 3 + score 4)/4

Replace what is known:

20 = (25 + 15 + 18 + p)/4

Simpligy:

20 = (58 +p) /4

Multiply both sides by 4:

80 = 58 + p

Subtract 58 from both sides:

p = 80 - 58

p = 22

7 0

2 years ago

On a map, 1 inch equals 5.2 miles. Two house are 3.5 inches apart on the map. What is the actual distance between the house?

MissTica

Answer:

18.2 miles

Step-by-step explanation:

simple multiplication:

We know that 1 inch of distance on the map is equal to 5.2 miles.

Using this knowledge we can multiply the amount of inches by the miles per inch.

5.2*3.5=18.2 miles apart

Hope this helps!!

4 0

2 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

2 years ago

Negative one fourths times negative six elevenths

Ipatiy [6.2K]

You multiply fractions simply by multiplying numerators and denominators with each other:

$-\dfrac{1}{4} \times \left(-\dfrac{6}{11}\right) = \dfrac{1 \times 6}{4 \times 11} = \dfrac{6}{44} = \dfrac{3}{22}$

3 0

2 years ago