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schepotkina [342]
2 years ago
14

Please help ASAP I hate maths and am so confused

Mathematics
1 answer:
sveta [45]2 years ago
5 0

Answer:

90 i think im sorry if its wrong

Step-by-step explanation:

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Giving brainliest and alot of points! A projectile is launched at an angle (θ) of 36° and travels a distance of 375 feet; gravit
abruzzese [7]

Answer:

(c) 112 ft/sec

Step-by-step explanation:

4 = 112.33 ft/sec = 112 ft/sec

6 0
1 year ago
Find the zeros of the function. Enter the solutions from least to greatest . h(x) = (- 4x - 3)(x - 3) lesser x = greater
icang [17]

9514 1404 393

Answer:

  -3/4, 3

Step-by-step explanation:

The zeros are the values of x that make h(x)=0. Those are the values of x that make the factors of h(x) be zero.

  -4x -3 = 0   ⇒   x = -3/4

  x -3 = 0   ⇒   x = 3

The zeros of the function are -3/4 and 3.

3 0
3 years ago
Which equation, when solved, results in a different value of x than the other three?
kicyunya [14]
I would have to say -7(1/8)x-4/3=20.


The first and the second one both result in
-23 5/7

The last one results in -24 8/21

but the third one is -22 3/8.

So your answer is either the third of the last one. I assumed the third because, it is lower than all others and the first two are closer to 24 than they are to 22. It’s your choice on how to judge it.
5 0
2 years ago
Every third visitors to a museum gets a free bumper sticker. Every fifth visitor to that museum gets a free key chain. Which vis
Rashid [163]
The fifteenth customer will be the first because 5x3=15

8 0
3 years ago
Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?
Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

\sin^2 \theta +\cos^2 \theta = 1

Let us solve this equation for cosine function.

\cos^2 \theta = 1-\sin^2 \theta

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

\cos \theta=\sqrt{1-\sin^2 \theta}

Thus, the correct option is: True; quadrants I & IV


6 0
3 years ago
Read 2 more answers
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