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3 years ago

What is the equation of the line that passes through the point (-6,3) and has a slope of -2/3?

Mathematics

1 answer:

Vesnalui [34]3 years ago

5 0

Answer:

$y = -\frac{2x}{3} - 1$

I hope this helps!

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11 - 2 x = 5x - 12 please help

babunello [35]

X is 23/7 i think .??

7 0

3 years ago

PQ is rotated 180 degrees clockwise about P. What are the coordinates of P' and Q'?

Salsk061 [2.6K]

The co ordinates of P' is (-7,-2) and Q' is (-16, -8)

Explanation

PQ is rotated 180 degrees clockwise about P. It means P and P' are the same points.

According to the graph, the coordinates of P is (-7, -2) and Q is (2, 4)

When PQ is rotated 180 degrees clockwise about P, then P or P' will be the mid-point of Q and Q'

Suppose, the co ordinate of Q' is (x, y)

Now according to the mid-point formula, the coordinate of P or P' will be: $(\frac{x+2}{2},\frac{y+4}{2})$ , which is actually at (-7, -2)

Thus.....

$\frac{x+2}{2}=-7\\ \\ x+2=-14\\ \\ x= -16\\ \\ and\\ \\ \frac{y+4}{2}= -2\\ \\ y+4= -4\\ \\ y= -8$

So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)

6 0

2 years ago

Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 65% chan

amm1812

Answer:

0.49

Step-by-step explanation:

We apply conditional probability to solve this question.

We have Events X and Events Y

P(X) = Probability Christine fails the course = ??? Unknown

P(Y) = Probability Christine finds a tutor

= 0.35

P(Y') = Probability Christine does not find a tutor = 1 - 0.35 = 0.75

P(X|Y) = Decrease in her probability of failing = 0.35

P(X|Y') = Probability that she will fail the course if she does not have a tutor

P(X) = P(X|Y) × P(Y) + P(X|Y') × P(Y')

P(X) = 0.35 × 0.75 + 0.65 × 0.35

P(X) = 0.2625 + 0.2275

P(X) = 0.49

The probability that Christine fails the course is 0.49

8 0

3 years ago

HELPPPP ASAPP !!!!

mr Goodwill [35]

Answer:

Probably A.

Step-by-step explanation:

Did the problem myself

6 0

2 years ago

A store sells black ink pens for $5 and red ink pens for $4. John wishes to buy 20 pens but doesn’t wish to spend more than $92.

Zina [86]

Answer: $4r + 5(20-r) \le 92$

=======================================

Explanation:

r = number of red pens

4r = cost of buying r red pens

example: if r = 10, then 4r = 4*10 = 40 is the total cost of buying 10 red pens

If John buys r red pens, then he must buy 20-r black pens so that r and 20-r add to 20.

John buys 20-r black pens, and at $5 each, so it will cost 5(20-r) dollars for just the black pens alone.

In total, John spends 4r + 5(20-r) dollars for all the pens (red & black)

We want $92 be the most he spends. This is the ceiling or highest value possible.

Therefore,

$4r + 5(20-r) \le 92$

--------------------

Extra info:

If you want to solve for r, then

$4r + 5(20-r) \le 92$

$4r + 5(20)+5(-r) \le 92$ distribute

$4r + 100 - 5r \le 92$

$100 - r \le 92$

$100-r+r \le 92+r$ add r to both sides

$100 \le 92+r$

$100-92 \le 92+r-92$ subtract 92 from both sides

$8 \le r$

$r \ge 8$

So John must buy at least 8 red pens. The most he can buy is 20 red pens since he wants 20 pens total.

8 0

2 years ago

What is the equation of the line that passes through the point (-6,3) and has a slope of -2/3?​

What is the equation of the line that passes through the point (-6,3) and has a slope of -2/3?