What is 69= 5(7-5r) + 4(r-2) show work

Mathematics

1 answer:

Serjik [45]2 years ago

4 0

Answer:

r=-2

Step-by-step explanation:

69=35-25r+4r-8 simplify

69=27-21r subtract 27 from both sides

42=-21r divide both sides by -21

r=-2

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Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

$k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0$

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3 years ago

Factoring by grouping how do i solve it 8r^3-64^2+r-8

Lelu [443]

Squaring a number is the same as multiplying the number by itself (64⋅64). In this case, 64 squared is 4096.
8r^3−4096+r−8

Subtract 8 from −4096 to get −4104.
8r^3−4104+r

Factor the polynomial using the rational roots theorem.
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2 years ago

Please Solve for x Log15 1 =x

Fiesta28 [93]