Yes, they are its just that the other one is smaller. Otherwise, they are the same
Answer: True
In math terms, an "image" is the result after a transformation has been applied. One or more transformations can happen here. The original figure is called the "preimage" or "before image" so to speak.
So we go from "preimage" to "image"
preimage ---> image
A maps to A'
B maps to B'
C maps to C'
D maps to D'
Ab9 is your answer my friend
Answer:
P_1st year = P0 x (1 + r/n) = P0 x (1 + r/n)^1
P_2nd year = P0 x (1 + r/n) (1 + r/n) = P0 x (1 + r/n)^2
...
P_n year = P0 x (1 + r/n)^n
Hope this helps!
:)
