The height of the rocket is found in terms of the angle as
.. h/(3 mi) = tan(θ)
.. h = (3 mi)*tan(θ)
Then the rate of change of height (vertical velocity) is
.. h' = (3 mi)*sec(θ)^2*θ'
.. h' = (3 mi)*4*(1.5 rad/min)
.. h' = 18 mi/min
The rocket's velocity is 18 miles per minute at that moment.
Divide 108 and 72 by twelve and you get 9 and 6 which all you have to do it multiply together
Answer:
Step-by-step explanation:
<em>The complete question is </em>
What is the length of line segment RS? Use the law of sines to find the answer. Round to the nearest tenth.
see the attached figure to better understand the problem
step 1
Find the measure of angle S
Applying the law of sines

substitute the given values

Solve for sin(S)

![S=sin^{-1}[sin(80^o)}{3.1}(2.4)]](https://tex.z-dn.net/?f=S%3Dsin%5E%7B-1%7D%5Bsin%2880%5Eo%29%7D%7B3.1%7D%282.4%29%5D)

step 2
Find the measure of angle Q
Remember that the sum of the interior angles in any triangle mut b equal to 180 degrees
so

substitute the given values
step 3
Find the length of segment RS
Applying the law of sines
substitute the given values
Answer:
Let
x = number of yards mowed
The domain of the function is
5 ≤ x ≤ 20
If we multiply the inequality by 25, we get
125 ≤ 25*x ≤ 500
Which is the same as
125 ≤ f(x) ≤ 500
(Range of the function)
Domain 5 ≤ x ≤ 20
Range 125 ≤ f(x) ≤ 500