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torisob [31]
3 years ago
15

Complete the method definition to output the hours given minutes. Output for sample program:3.5import java.util.Scanner;public c

lass HourToMinConv { public static void outputMinutesAsHours(double origMinutes) { /* Your solution goes here */ } public static void main (String [] args) { Scanner scnr = new Scanner(System.in); double minutes; minutes = scnr.nextDouble(); outputMinutesAsHours(minutes); // Will be run with 210.0, 3600.0, and 0.0. System.out.println(""); }}
Computers and Technology
1 answer:
Aliun [14]3 years ago
8 0

Answer:

import java.util.Scanner;

public class num1 {

   public static void outputMinutesAsHours(double origMinutes) {

       double hours = origMinutes / 60;

       System.out.println("The converted hours is " + hours);

   }

   public static void main(String[] args) {

       Scanner scnr = new Scanner(System.in);

       double minutes;

       minutes = scnr.nextDouble();

       outputMinutesAsHours(minutes); // Will be run with 210.0, 3600.0,

       System.out.println("");

   }

}

Explanation:

The question required us to only write the statement to complete the line

outputMinutesAsHours(double origMinutes) { /* Your solution goes here */ }

The solution double hours = origMinutes / 60; solves this because there are 60 minutes in one hour, so to conver minutes to hours, you divide the number of minutes by 60

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Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and s
S_A_V [24]

Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

int main() {

//  variable  

int num;

cout<<"Enter the number between 20 and 98: ";

// read number

cin >> num;

while(num<20||num>98)

{

   cout<<"Wrong input!!enter number between 20-98 only:";

   cin>>num;

}

cout<<"The output is: ";

while(num % 10 != num /10)

{

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// update num.

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cout<<num<<endl;;

return 0;

}

Explanation:

Read a number from user and assign it to variable "num".Check if entered number  is in between 20-98 or not.If input number is less than 20 or greater than 98 then  ask again to enter a number between 20-98 until user enter a valid input.Then print  the countdown from input number till both the digit of number are same.

Output:

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Wrong input!!enter number between 20-98 only:12                                                                            

Wrong input!!enter number between 20-98 only:93                                                                            

The output is: 93 92 91 90 89 88

Enter the number between 20 and 98: 77                                                                                    

The output is: 77

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