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torisob [31]
3 years ago
15

Complete the method definition to output the hours given minutes. Output for sample program:3.5import java.util.Scanner;public c

lass HourToMinConv { public static void outputMinutesAsHours(double origMinutes) { /* Your solution goes here */ } public static void main (String [] args) { Scanner scnr = new Scanner(System.in); double minutes; minutes = scnr.nextDouble(); outputMinutesAsHours(minutes); // Will be run with 210.0, 3600.0, and 0.0. System.out.println(""); }}
Computers and Technology
1 answer:
Aliun [14]3 years ago
8 0

Answer:

import java.util.Scanner;

public class num1 {

   public static void outputMinutesAsHours(double origMinutes) {

       double hours = origMinutes / 60;

       System.out.println("The converted hours is " + hours);

   }

   public static void main(String[] args) {

       Scanner scnr = new Scanner(System.in);

       double minutes;

       minutes = scnr.nextDouble();

       outputMinutesAsHours(minutes); // Will be run with 210.0, 3600.0,

       System.out.println("");

   }

}

Explanation:

The question required us to only write the statement to complete the line

outputMinutesAsHours(double origMinutes) { /* Your solution goes here */ }

The solution double hours = origMinutes / 60; solves this because there are 60 minutes in one hour, so to conver minutes to hours, you divide the number of minutes by 60

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Suppose list1 is an MyArrayList and list2 is a MyLinkedList. Both contains 1 million double values. Analyze the following code:
hjlf

Answer:

The correct answer for the given question is " The Code fragment A runs fastly than the code fragment of B".

Explanation:

In this question there are some information is missing i. e options. The question does not give any options. The options for the given question is given below

(A.) The Code fragment A runs fastly than the code fragment of B.

(B.) The Code fragment B runs fastly than code fragment of  A.

(C)  The Code fragment A runs as fastly as code fragment of B.  

So we conclude the answer i.e option(A) because As given in the question list1  is a MyArrayList and list2 is a MyLinkedList.  , in list1 we fetching the data easily and fastly means that it remove the data easily as compare to list2 As MyArrayList is storing the list only and also we can fetch the data easily manner.

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4 years ago
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zimovet [89]

Answer:

The program in Python is as follows:

from operator import itemgetter

m = int(input("Number of records: "))

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Explanation:

This imports the operator function from itemgetter

from operator import itemgetter

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This prints the format of input

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my_list.sort(key =  itemgetter(0, 1, 2))        

This prints the sorted tuple

print("Sorted: ", my_list)

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