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3 years ago

Find the side of a square whose diagonal is of the given measure. Given = 15.2 cm

Mathematics

2 answers:

Neko [114]3 years ago

8 0

Answer:

15cm

Step-by-step explanation:

First, a square's diagonal is basically the hypotenuse of a 45-45-90 triangle. a 45-45-90 triangle has a really special relationship, where the side length is x, and the diagonal is x $\sqrt{2}$ . So, the side length is 15.

Marat540 [252]3 years ago

3 0

Answer:

15cm

Step-by-step explanation:

Each corner of the square would be a 90° angle so half of that would be 45°.

$\sin(45) \times 15 \sqrt{2} = 15cm$

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Can someone answer this question please (picture)

erik [133]

Answer:

31.5 units^2

Step-by-step explanation:

Rectangle area (RA) = l × w

Triangle area (TA) = (bh)/2

RA = 3 × 7

RA = 21

TA = (7 × 3)/2

TA = 21/2

TA = 10.5

(Triangles are congruent as shown by the lines on each side of the triangle so I can calculate area of both of them together as I just did)

Add areas together

21 + 10.5 = 31.5

7 0

3 years ago

Video Example EXAMPLE 1 Find the linearization of the function f(x) = x + 1 at a = 3 and use it to approximate the numbers 3.98

Blizzard [7]

Answer:

the linearization is y = 1/4x +5/4

the linearization will produce overestimates

the values computed from this linearization are ...

f(3.98) ≈ 2.245

f(4.05) ≈ 2.2625

Step-by-step explanation:

Apparently, you have ...

$f(x)=\sqrt{x+1}$

from which you have correctly determined that ...

$f'(x)=\dfrac{1}{2\sqrt{x+1}}$

so that f(3) = 2 and f'(3) = 1/4. Putting these values into the point-slope form of the equation of a line, we get the linearization ...

g(x) = (1/4)(x -3) +2

g(x) = (1/4)x +5/4

The values from this linearization will be overestimates, as the curve f(x) is concave downward everywhere. The tangent (linearization) is necessarily above the curve everywhere.

At the given values, we find ...

g(3.98) = 2.245

g(4.05) = 2.2625