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3 years ago

11

If there are 400 cubic centimeters of a chemical in 1 liter of solution, how many cubic centimeters of water must be added to di

lute it to a 25% solution?

1 answer:

mars1129 [50]3 years ago

5 0

$1l=1dm^3\\1dm=10cm\to1dm^3=(10cm)^3=1000cm^3\\\\1l=1000cm^3\\-------------\\ \begin{array}{ccc}400cm^3&-&25\%\\1000cm^3+x&-&100\%\end{array}\\cross\ multiply\\25(1000+x)=400\times100\\25000+25x=40000\ \ \ \ \ |subtract\ 25000\ from\ both\ sides\\25x=15000\ \ \ \ |divide\ both\ sides\ by\ 25\\\boxed{x=600\ (cm^3)}\\\\Answer:Must\ be\ added\ 600cm^3\ of\ water.$

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Answer:

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Step-by-step explanation:

Let

x ----> the measure of the shortest side

y ---> the measure of the middle side

z ---> the measure of the longest side

we know that

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so

$3,067=x+y+z$ ----> equation A

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so

$x=y-71$ ----> equation B

the longest side measures 372 mi more the the middle side

so

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substitute equation B and equation C in equation A

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$3,067=3y+301\\3y=2,766\\y=922$

Find the value of x

$x=y-71\\x=922-71\\x=851$

therefore

The measure of the shortest side is 851 miles

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