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bulgar [2K]
4 years ago
11

If there are 400 cubic centimeters of a chemical in 1 liter of solution, how many cubic centimeters of water must be added to di

lute it to a 25% solution?
Mathematics
1 answer:
mars1129 [50]4 years ago
5 0
1l=1dm^3\\1dm=10cm\to1dm^3=(10cm)^3=1000cm^3\\\\1l=1000cm^3\\-------------\\  \begin{array}{ccc}400cm^3&-&25\%\\1000cm^3+x&-&100\%\end{array}\\cross\ multiply\\25(1000+x)=400\times100\\25000+25x=40000\ \ \ \ \ |subtract\ 25000\ from\ both\ sides\\25x=15000\ \ \ \ |divide\ both\ sides\ by\ 25\\\boxed{x=600\ (cm^3)}\\\\Answer:Must\ be\ added\ 600cm^3\ of\ water.
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meg has $20 in a savings account that earns 10% annually. the interest is not compounded. how much will she have in 1 year
snow_tiger [21]
<h2>Answer: 22$</h2>

Step-by-step explanation: 10% of 20 is 2 so 20 + 2 = 22.

Hope this helps! ;)

4 0
3 years ago
Two chemists working for a chicken fast-food company, have been producing a very popular sauce. Let’s call then Jesse and Mr. Wh
a_sh-v [17]

Answer:

Check the explanation

Step-by-step explanation:

Let \overline{x} and \overline{y} be sample means of white and Jesse denotes are two random variables.

Given that both samples are having normally distributed.

Assume \overline{x} having with mean \mu_{1} and \overline{y} having mean \mu_{2}

Also we have given the variance is constant

A)

We can test hypothesis as

H0: \mu_{1} =  \mu_{2}H1: \mu_{1} > \mu_{2}

For this problem

Test statistic is

T=\frac{\overline {x}-\overline {y}}{s\sqrt{\frac {1}{n1} +\frac{1}{n2}}}

Where

s=\sqrt{\frac{(n1-1)*s1^{2}+(n2-1)*s2^{2}}{n1+n2-2}}

We have given all information for samples

By calculations we get

s=2.41

T=2.52

Here test statistic is having t-distribution with df=(10+7-2)=15

So p-value is P(t15>2.52)=0.012

Here significance level is 0.05

Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.

We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.

3 0
3 years ago
The average speed of a car is three times as fast as the average speed of a cyclist. to travel 225 km, the cyclist requires 5 h
Bumek [7]
Average speed of cyclist = x
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x = 225/5
x = 45km/h

3x = 3(45)
3x = 135km/h

average speed of cyclist = 45km/h
average speed of car = 135km/h
6 0
3 years ago
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