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julia-pushkina [17]
3 years ago
6

In a lottery​ game, a single ball is drawn at random from a container that contains 25 identical balls numbered from 1 through 2

5. find the probability that the number drawn is a multiple of 77 or a multiple of 4.
Mathematics
1 answer:
Vesna [10]3 years ago
7 0
Total numbers = 1-25 = 25 numbers

Multiples of 77: 1, 7, 11
Multiples of 4: 1, 2, 4

Therefore, multiples of 77 or 4 are: 1, 2, 4, 7, 11 = 5 numbers

P (multiples of 7 or 4) = 5/25 = 1/5 = 0.2

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What is the equation of the line that passes through the point
snow_lady [41]

Answer:

3x-2y=2

Step-by-step explanation:

The equation of line having slope \frac{3}{2} and passing through (-4,-7).

The\ equation\ of\ line\ is\ given\ by\ y=mx+c\ where\ m\ is\ the\ slope\ of\ line.\\\\Here\ m=\frac{3}{2}\\\\Equation\ y=\frac{3}{2}x+c\\\\Line\ passes\ through\ (-4,-7),\ it\ will\ satisfy\ the\ equation\ of\ line.\\\\-7=\frac{3}{2}\times (-4)+c\\\\-7=-6+c\\\\c=-7+6\\\\c=-1\\\\y=\frac{3}{2}x-1\\\\2y=3x-2\\\\3x-2y=2

8 0
4 years ago
Which expression is equivalent to ( 4 1/3)^3 ?
KIM [24]

Answer:

B: 4^1

Step-by-step explanation:

6 0
3 years ago
The cylinder’s diameter and height are both 39.2 millimeters. What is the surface area of this cylinder?
Dominik [7]

Answer:

A = 7,241.2454026112  square mm.

or exact : A = 2,304.96‬*π  sq mm

Step-by-step explanation:

Cylinder formula:   A = π* r^2 +  2 *π * r* h  +  π*r^2

is the surface area.

d = 2r = 39.2 mm

h = 39.2 mm

r = 19.6 mm

A = π* r^2 +  2 *π * r* h  +  π*r^2

A = 2* π* (19.6)^2  + 2π (19.6)*(39.2)  

A = 2,413.748467537 +  4,827.496935

A = 7,241.2454026112  square mm.

or

A =  2*pi* (768.32‬ + 384.16)

A = 2*1,152.48‬* pi

A = 2,304.96‬*π  sq mm

8 0
3 years ago
Please could someone help with this ? Thankyou
katovenus [111]

Answer:

1 2/7

Step-by-step explanation:

4.5:3 1/2

45/10 ÷ 7/2

45/10 x 2/7

90/70=9/7

=1 2/7

4 0
3 years ago
Read 2 more answers
A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
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