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VikaD [51]
3 years ago
12

Can someone answer this it’s urgent

Mathematics
1 answer:
RideAnS [48]3 years ago
7 0

Answer:

I don`t know about IQR but...

A:

Range = 50

Median = 105

Minimum = 80

Maximum = 130

B: 75%

C: 50%

D: 25%

E: 130%

Step-by-step explanation:

It izz wat it izzzz!!!

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Step-by-step explanation:

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A California water company has determined that the average customer billing is $1,250 per year and the amounts billed have an ex
Tcecarenko [31]

Answer:

a)

Mean \mu = \dfrac{1}{\lambda }= 1250

\lambda = \dfrac{1}{1250}

b)

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c)

P(X > 1250) =0.3679

Step-by-step explanation:

From the given information:

a.)

Mean \mu = \dfrac{1}{\lambda }= 1250

\lambda = \dfrac{1}{1250}

Let consider X to be a random variable that follows an exponential distribution; then:

P(X) = 1 - e^{- \lambda x}   since \lambda > 0

b.)

The required probability that a random chosen customer would spend more than $5,000 can be computed as:

P(X > 5000) = 1  - \bigg [ 1 - e ^{- \dfrac{5000}{1250}}  \bigg]

P(X > 5000) =e^  {-4

P(X > 5000) = 0.0183

c.)

P(X > 1250) = 1  - \bigg [ 1 - e ^{- \dfrac{1250}{1250}}  \bigg]

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P(X > 1250) =0.3679

7 0
2 years ago
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