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Artyom0805 [142]
3 years ago
14

suppose that two current exchange rates are US $1 = 117.9 Yen and 1 peso = US $0.0476. What is the value of 1 peso in yen?

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0
1245 is your answer u welcome !!!!!!!!!
You might be interested in
Find the answer to 3(q+34)=2
xz_007 [3.2K]

Hey there!

3(q + 34)= 2

First distribute:

3(q) + 3(34)

3(q) = 3q

3(34) = 102

New equation: 3q + 102 = 2

Subtract by 102 on each of your sides:

3q + 102 - 102 = 2 - 102

Cancel out: 102 - 102 because it gives us 0

Keep: 2 - 102 because it helps us solve for our q

2 - 102 = - 100

New equation: 3q = -100

Divide both sides by 3

3q/3 = -100/3

Cancel out: -3q/3 because it gives us 1

Keep: -100/3 because it gives us the answer for q

Answer: q = -100/3 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

8 0
3 years ago
Decrease 18 tonnes by 30%
AVprozaik [17]
18 t - 18 t * 30% = 18 t - 17 * 0,3 = 18 t - 5,4 t = 12,6 t
5 0
2 years ago
Gianna invested $30,000 in an account paying an interest rate of 1.9% compounded
Ganezh [65]

Answer:

5,095,068

Step-by-step explanation:

The equation for this problem is x^y * z where x is the percentage, Y is the number of years, and Z is the original deposit. Multiply 1.9^8 * 30,000 which becomes; 5,095,068.

Whoever has that bank account is going to be very rich.

3 0
3 years ago
Can someone help me please? Am I right or no?
Juliette [100K]
The figure consists of three objects, a rectangle, a trapezoid, a triangle

Find the area of the rectangle
The rectangle is 16 in long and 9 in wide
a₁ = l × w
a₁ = 16 × 9
a₁ = 144 in²

Find the area of the trapezoid
The base of trapezoid is 31 in and 16 in, and the height is 35 - 20 = 15 in.
a₂ = 1/2 × (a + b) × h
a₂ = 1/2 × (31 + 16) × 15
a₂ = 1/2 × 47 × 15
a₂ = 352.5 in²

Find the area of the triangle
The base of the triangle is 31 in, the height is 20 in
a₃ = 1/2 × b × h
a₃ = 1/2 × 31 × 20
a₃ = 310 in²

Add the area together
a = a₁ + a₂ + a₃
a = 144 + 352.5 + 310
a = 806.5

The answer is 806.5 in²
4 0
2 years ago
A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCI/L of radon. The resulting reading
valkas [14]

Answer:

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

p_v =2*P(t_{11}  

Step-by-step explanation:

1) Data given and notation  

Data: 105.6, 90.9, 91.2, 96.9, 96.5, 91.3, 100.1, 105.0, 99.6, 107.7, 103.3, 92.4

We can calculate the sample mean and deviation for this data with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

The results obtained are:

\bar X=98.375 represent the sample mean  

s=0.6.109 represent the sample standard deviation  

n=12 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 100pCL/L, the system of hypothesis are :  

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

4) P-value  

First we need to find the degrees of freedom for the statistic given by:

df=n-1=12-1=11

Since is a two sided test the p value would given by:  

p_v =2*P(t_{11}  

5) Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significant different from 100 at 5% of significance.  

3 0
3 years ago
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