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stellarik [79]
4 years ago
9

X and y intercepts 2x-2y=-4

Mathematics
1 answer:
Amanda [17]4 years ago
4 0
I think that you are asking for the slope intercept so in order to get y=mx+ b mx=slope b= y-intercept. You goal is to get the Y by itself and equal to 1 so 2x-2y= -4 -2x -2x (^this gets cancelled out) -2y= -2x -4 /-2 /-2 /-2 Y= 1/2 + 2
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I need help with this question fast! i don't have a lot of time! can someone help me please???
jarptica [38.1K]
16x^4-81y^4  difference of perfect squares...

(4x^2-9y^2)(4x^2+9y^2)  that's one of the equivalents...

(2x+3y)(2x-3y)(4x^2+9y^2)  that's another one of them...
5 0
3 years ago
An individual is planning a trip to a baseball game for 16 people. Of the people planning to go to the baseball game, 8 can go o
Sedaia [141]

Answer: There are 4 people who only go to the game on Saturday.

Step-by-step explanation:

Let the number of people go on Saturday be n(A).

Let the number of people go on Sunday be n(B).

Since we have given that

n(A) = 8

n(B) = 12

n(A∪B)  = 16

According to rules, we get that

n(A)+n(B)-n(A\cap B)=n(A\cup B)\\\\8+12-n(A\cap B)=16\\\\20-n(A\cap B)=16\\\\n(A\cap B)=20-16=4

So, n(only go on Saturday) = n(only A) = n(A) - n(A∩B) = 8-4 = 4

Hence, there are 4 people who only go to the game on Saturday.

4 0
3 years ago
HELP MEE ILL GIVE BRAINLIEST!!
solniwko [45]

Answer:

16 by 8

Step-by-step explanation:

3 0
3 years ago
Solve the following equation for y: 35x-7y=49​
Brrunno [24]
The answer is Y equals -7+5x
5 0
3 years ago
Read 2 more answers
Write an equation of a line that is perpendicular to y=2x-3 and has a y intercept of 10
AnnyKZ [126]
The slope of a line that is perpendicular to another line is the negative reciprocal of the other.

In this case, we know that the slope of the given equation is 2.

Since we're solving for a line perpendicular to it, we simply find the reciprocal of the 2 (It turns into 1/2) and make it negative.

y = -1/2x + b

Since the given states that the new y-intercept is 10, input it into 'b'.

y = -1/2x + 10


If you'd like me to explain anything I did here, just ask :)
-T.B.
4 0
3 years ago
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