Almost got it!
x + 3 = 3(y + 2)/2 [Multiplied both sides by 3]
so x + 3 = (3y + 6)/2
2(x + 3) = 3y + 6 [Multiplied both sides by 2]
2x + 6 = 3y + 6
2x = 3y [Subtracted 6 from both sides]
x = 3y/2 [Divided both sides by 2]
x/3 = y/2 [Divided both sides by 3]
So you wrote y/3 instead of y/2
Hope this helped!
Answer: The answers are 13. (A) and 14. (B).
Step-by-step explanation: The calculations are as follows:
(13) The given equations are

In the attached figure (a), these two lines are drawn. We can see that The lines intersect at the point P(8, -9). So, the solution to the pair of equations is (8, -9).
Thus, the correct option is (A).
(14) The given equations are

In the attached figure (b), these two lines are drawn. We can see that The lines intersect at the point Q(7, -2). So, the solution to the pair of equations is (7, -2).
Thus, the correct option is (B).
Answer:
c
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hi there,
If the boy wants 80 small action figures
that is equivalent to 40 x 7 (as 7 tickets
gives him 2 small action figures)
= 280 tickets.
The 380 tickets he has originally minus the
280 leaves 100 tickets to get 20 large action figures
(100/5)
He will have 80 small and 20 large action figures
80:20 = 4:1
Hope this helps:-)
Answer: the answer is C
Step-by-step explanation: