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Levart [38]
3 years ago
10

Two consecutive even whole numbers are selected. The difference between the reciprocals of the two numbers is 1/60. Determine th

e two numbers.
Mathematics
1 answer:
sammy [17]3 years ago
6 0

let the 2 numbers be x and x + 2
since they are 2 consecutive even numbers, the difference between them is 2
the difference between the reciprocals is 1/60 
\frac{1}{x+2} -  \frac{1}{x} =  \frac{1}{60}
we have to mulitply the 2 denominators x and (x+2) to get a common denominator for the 2 fractions 
\frac{x - (x+ 2)}{x(x+ 2)} = \frac{1}{60}
we can then remove the brackets from the numerator and denominator 
\frac{x-x+2}{ x^{2} +2x }  =  \frac{1}{60}
and then cross multiply
60 * 2 = x² + 2x
120 = x² + 2x
x² + 2x - 120 = 0
we have a quadratic equation which needs to be solved 
x² + 12x - 10x - 120 = 0
x (x + 12) - 10(x + 12) = 0
(x - 10) (x + 12) = 0
x - 10 = 0     or   x + 12 = 0
x = 10                x = -12
since we haven't been told if the whole numbers are positive or negative, 
2 numbers could be 10 and 12 
or
- 12 and - 10 
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(4,-16) factor 3/4
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B' (3,-12)
5 0
3 years ago
Martha needs 28 strawberries for every 4 smoothies she makes. Complete the table using equivalent ratios.
S_A_V [24]

answer: 28: 4

21: 3

70: 10

step-by-step explanation:

divide 28 by 4, and of course, do to the bottom what you do to the top. 4 divided by 4 is 1, and 28 divided by 4 is 7.

7: 4.

then, multiply by the number of smoothies.

for 3, it's 21: 3.

for 10, it's 70: 10.

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3 years ago
Pls help I will give Brainiest sorry if I spellt it wrong
devlian [24]

Answer:

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Step-by-step explanation:

5 0
2 years ago
What is the true solution to the logarithmic equation below?<br> log₂ (6x)-log₂ (√x)=2
slega [8]

Answer:

The true solution is x=4/9

EXPLANATION

The logarithmic equation given to us is

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When we apply this law the expression becomes

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We square both sides to get,

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6 0
2 years ago
Read 2 more answers
It is given that y varies inversely as x^2. If x is decreased by 50%, find the percentage change in y.
vova2212 [387]

Answer:

300%

Step-by-step explanation:

Given

y\ \alpha\ \frac{1}{x^2}

Required

Find the percentage change in y when x decreased by 50%

First, convert to equation

y\ = \ \frac{k}{x^2}

Where k is the constant of proportionality

When x decreased by 50%

Y = \frac{k}{(x - 0.5x)^2}

Y = \frac{k}{(0.5x)^2}

Y = \frac{k}{0.25x^2}

Expand

Y = \frac{1}{0.25} * \frac{k}{x^2}

Substitute \frac{k}{x^2} for y

Y = \frac{1}{0.25} * y

Y = 4 * y

Y = 4 y

The percentage change is then calculated as:

\%Change = \frac{Y - y}{y} * 100\%

\%Change = \frac{4y - y}{y} * 100\%

\%Change = \frac{3y}{y} * 100\%

\%Change = 3 * 100\%

\%Change = 300\%

<em>The percentage in y is 300%</em>

7 0
3 years ago
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