Answer:
D. 4 ft.
Step-by-step explanation:
Diagonals are the lines that extend from one corner of the square/rectangle to the opposing/reflectory side. So an example of a diagonal would be from the upper left hand corner of this shape to the lower right hand corner. This would be a diagonal. Since We know that both diagonals intersect at the center, each diagonal halves itself. So, since we know that 1/2 of a diagonal = 2 feet, then if we add the second half of the diagonal, or 2 more feet, we get the length of a diagonal.
2 ft. + 2 ft. = 4 ft.
And since the lengths of diagonals in squares and rectangles are congruent, we can see that if one diagonal is equal to 4 ft., then the length of the other diagonal will also be 4 ft.
keeping in mind that 4 months is not even a year, since there are 12 months in a year, 4 months is then 4/12 years.
let's assume is simple interest.
![\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$34300\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ t=years\to \frac{4}{12}\dotfill &\frac{1}{3} \end{cases} \\\\\\ A=34300\left[ 1+(0.035)\left( \frac{1}{3} \right) \right]\implies A= 34300(1.011\overline{6})\implies A=34700.1\overline{6}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%2434300%5C%5C%20r%3Drate%5Cto%203.5%5C%25%5Cto%20%5Cfrac%7B3.5%7D%7B100%7D%5Cdotfill%20%260.035%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B4%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B1%7D%7B3%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D34300%5Cleft%5B%201%2B%280.035%29%5Cleft%28%20%5Cfrac%7B1%7D%7B3%7D%20%5Cright%29%20%5Cright%5D%5Cimplies%20A%3D%2034300%281.011%5Coverline%7B6%7D%29%5Cimplies%20A%3D34700.1%5Coverline%7B6%7D)
F(x) = x^2 + 5x
F(5) = 5^2 + 5(5)
F(5) = 25 + 25
F(5) = 50
G(x) = 2x + 1
G(6) = 2(6) + 1
G(6) = 12 + 1
G(6) = 13
F(5) + G(6) = 50 + 13 = 63 <==
Answer:
Step-by-step explanation:
9x^2 + 24x + 16 = 0
(3x + 4)(3x+4)=0
3x + 4 = 0
3x = -4
x = -4/3
3x + 4 = 0
3x = -4
x = -4/3
Forget the 1996 for the moment. Just count the number of years that go by.
30500*(1.02)^x= 32500 + 600x The easiest way to handle this is either to use a spreadsheet or graph if. I don't see an algebraic way of doing it. I'll try the graph first.
The red line is y = 32500 + 600x
Now let's try a spreadsheet.
I can't copy and past a spreadsheet's contents, but it shows that they are about equal when x = 17.
y = 32500 + 600x gives 42700 when x = 17
y = 30500*(1.02)^17 gives 42707 when x = 17 You cannot get much closer than that.