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Elena-2011 [213]
3 years ago
10

Marcus bought a rug that is 6 meters long. Vinny bought a rug that is 3/4 as long as Marcus's rug. How long is Vinny's rug?

Mathematics
2 answers:
mash [69]3 years ago
5 0

Answer:

4.5 meters

Step-by-step explanation:

6*.75=4.5

We need to multiply the 6 by 3/4 (.75) because it would be the same if it were 2 times as long, the only difference is that the answer will be smaller.

Reika [66]3 years ago
5 0

Answer:

4.5

Step-by-step explanation:

(There are multiple ways to do this but I thought this was easier)

Vinny's rug is 3/4 as long as Marcus's 6 meter rug.

3/4 equals .75

.75 x 6 = 4.5

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Step-by-step explanation:

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3 years ago
Write 7x7x7 usiang a exponent
vodka [1.7K]
7^3 is the same as 7x7x7
7 0
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Which expression is represented by the phrase "the square of y decreased by the quotient of 28 and 7?
agasfer [191]

Answer:

y^{2}-4

Step-by-step explanation:

We are given the statement,

'The square of y decreased by the quotient of 28 and 7'.

i.e. Subtracting the quotient \frac{28}{7} = 4 from y^{2}.

i.e. y^{2}-4

Hence, the expression which represents the given statement is y^{2}-4.

4 0
3 years ago
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Kimberly has driven
NARA [144]

Answer: 300.

Step-by-step explanation: 225/(No denominator) = 75/100.

225 doesn't go in 75. So, 75/100 divided by 5 = 15/20.

I want to find what number you multiply from 15/20 to get 225/(No

denominator). So, I divide 225 by 15. = 15, so multiply 15 x 15 = 225, and

the denominator, 20 x 15= 300.

(Sorry if you don't understand, I don't really know how to explain things.)

But here's your answer!

8 0
3 years ago
10. (a) Consider the following matrices: A = ( 2 ) B = (3) and C = (-3) w = Find the det(A). [1] (ii) Is the matrix A singular?
Viefleur [7K]

i) We have to find the determinant of A.

We can do this as:

\det(A)=|\begin{bmatrix}{3} & {6} \\ {1} & {-2}\end{bmatrix}|=3*(-2)-6*1=-6-6=-12

ii) We have to find if the matrix A is singular.

Singular matrix have determinant equal to 0.

This is not the case for A, as its determinant is -12. Then, A is not a singular matrix.

iii) We have to find the values of x and y so that AB = C.

We have to write the matrix multiplication and we will obtain a system of linear equations:

We can now solve the system of equations by adding 3 times the second equation to the first equation:

\begin{gathered} 3(x-2y)+(3x+6y)=3(-3)+(-3) \\ 3x-6y+3x+6y=-9-3 \\ 6x+0y=-12 \\ x=\frac{-12}{6} \\ x=-2 \end{gathered}

We can now use the second equation to find the value of y:

\begin{gathered} x-2y=-3 \\ x+3=2y \\ y=\frac{x+3}{2} \\ y=\frac{-2+3}{2} \\ y=\frac{1}{2} \end{gathered}

The values are x = -2 and y = 1/2.

iv) When we want to multiply two matrices, the required condition is that the number of columns of the matrix on the left is equal the number of rows of the matrix on the right.

In the case of A(2x2) and B(2x1), when we do A*B this condition is satisfied.

But when we try to multiply BA, the number of columns of B is not equal to the number of rows of A, so the matrix mulitplication is not possible.

Answer:

i) det(A) = -12

ii) A is not singular because singular matrices have determinant equal to zero.

iii) x = -2 and y = 1/2.

iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.

6 0
1 year ago
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