3. The answer is 18 because 12➗4= 3 so 6*3=18
Answer:
BC ≈ 4.0
Step-by-step explanation:
∠ DCA = 180° - 70° = 110° ( adjacent angles )
∠ DAC = 180° - (30 + 110)° ← sum of angles in triangle
∠ DAC = 180° - 140° = 40°
Using the Sine rule in Δ ACD to find common side AC
=
( cross- multiply )
AC × sin40° = 15 × sin30° ( divide both sides by sin40° )
AC =
≈ 11.668
Using the cosine ratio in right triangle ABC
cos70° =
=
=
( multiply both sides by 11.668 )
11.668 × cos70° = BC , then
BC ≈ 4.0 ( to the nearest tenth )
Answer:
The amount of gold used in a 200 g 14 gold bracelet is 116 g.
Step-by-step explanation:
Since a 14 karat jewell is stated to have aproximally 58 % of it's weigh in gold we need to take the total weigh of the jewel in question and find that percentage of it's weigh. In order to find that percentage we'll first convert that number into a decimal, we do that by dividing it by 100, so we have 58% = 58/100 = 0.58 we can multiply this value by the weigh of the jewel to find the amount of gold used. So we have:
gold used = total weigh*0.58 = 200*0.58 = 116 g
Answer:
since M lies between point A and B , we came to know that,
M(4,6) =(x,y)
A(-2,-1)=(x1 ,y1)
B( _, _ )=(x2,y2)
Now using mid point formula,
x=x1×x2÷2 y=y1+y2÷2
so, point B is (10,13)
Answer:
the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.
Step-by-step explanation:
The variation of the concentration of salt can be expressed as:

being
C1: the concentration of salt in the inflow
Qi: the flow entering the tank
C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)
Qo: the flow going out of the tank.
With no salt in the inflow (C1=0), the equation can be reduced to

Rearranging the equation, it becomes

Integrating both sides

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

The final equation for the concentration of salt at any given time is

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:
