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Murrr4er [49]
3 years ago
7

What pairs have the least common multiple of 45

Mathematics
2 answers:
Sladkaya [172]3 years ago
7 0
The answer is 1,3,5,9,15,and ofcourse 45
ololo11 [35]3 years ago
3 0
For two numbers (let's call them a & b), the least common multiple is the smallest number that is an integer multiple of both a and b.  For example, given the numbers 12 and 18, their least common multiple is 36, because of 3x12=36 and 2x18=36.  A least common multiple can never be greater than the product of the two numbers because b times a is the b-the multiple of a, and the a the multiple of b.  For example, the least common multiple of 7 and 11 is 77 because multiples of 7 are 14, 21, 28, 35, 42, 49, 56, 63, 70 and 77 and multiples of 11 are 22, 33, 44, 55, 66, 77, so 77 is the first one that is a multiple of both numbers.  (BTW, 7 & 11 can be your first pair).The least common multiple of two numbers is the product of the two numbers when those numbers are relatively prime to each other, that is to say, that the two numbers do not share a factor in common (except for 1).  For example, the least common multiple of 9 and 8 is their product 72.  While neither 9 nor 8 are prime numbers, the factors of 9 are 3*3 and of 8 are 2*2*2.  Since they share no factors in common, their product will be the least common multiple.  (Multiples of 9 are 18, 27, 36, 45, 54, 63, and 72; Multiples of 8 are 16, 24, 32, 40, 48, 56, 64, and 72).  (BTW, 8 & 9 could be your 2nd pair.So to construct a pair of numbers whose product is their least common multiple all you need to do is create two lists of prime factors, one for each number, where none of their factors overlap.  While a number can be on one list multiple times (like the number 2 for 8 or the number 3 for 9), the same number cannot be on the list for both a and b.  The first six prime numbers are 2, 3, 5, 7, 11, and 13.  You can mix and match them however you'd like (following the rule above) to create your third pair of numbers.  If you comment your choice, I'd be happy to confirm whether you have successfully constructed such a pair.                  -Hope this help #Hackerhelper
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What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?
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The equation of the line parallel to given line and passing through (-3, 1) will be y – 1 = (3/2)(x + 3). Then the correct option is D.

<h3>What is the equation of line?</h3>

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

The slope of the parallel lines are equal.

m = (2 + 4) / (2 + 2)

m = 6/4

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Then the equation of the line will be

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Then the equation will be

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Then the correct option is D.

More about the equation of line link is given below.

brainly.com/question/21511618

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Read 2 more answers
Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3
chubhunter [2.5K]

Answer:

The simplified form is \dfrac{2(x-1)}{3(x+1)}.

x =1 is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

\dfrac{2a^2-4a+2}{3a^2-3}

Let us simplify the numerator and denominator separately.

The numerator is given as 2a^2-4a+2

2 is a common factor in all the three terms. So, we factor it out. This gives,

=2(a^2-2a+1)

Now, a^2-2a+1=(a-1)(a-1)

Therefore, the numerator becomes 2(a-1)(a-1)

The denominator is given as: 3a^2-3

Factoring out 3, we get

3(a^2-1)

Now, a^2-1 is of the form a^2-b^2=(a-b)(a+b)

So, a^2-1=(a-1)(a+1)

Therefore, the denominator becomes 3(a-1)(a+1)

Now, the given expression is simplified to:

\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}

There is (x-1) in the numerator and denominator. We can cancel them only if x\ne1 as for x=1, the given expression is undefined.

Now, cancelling the like terms considering x\ne1, we get:

\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}

Therefore, the simplified form is \dfrac{2(x-1)}{3(x+1)}

The simplification is true only if  x\ne1. So, x =1 is the excluded value for the given expression.

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4 years ago
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