2. y=x-3
3. y=3x+1
4. y=-3x-3
Substitution is best to use one one or both equations is already solved for one of the variables. Elimitation can be use if all variables have a coefficient other than 1.
Answer:
1. 30j+12+6j
2. 36j+12
3. 6(6j+2)
Step-by-step explanation:
1. You just multiply so... 6x5j ... 6x2 ... 6xj
2. you multiply and then simplify so first you have 30j+12+6j, so you add like terms so... 30j+6j= 36j and then +12
3. you do what's in the parentheses first so 5j+j=6j so .... 6(6j+2)
Part A: 3x + 15 = 5x - 25
Part B: x = 20
Answer:
x = 4
y = 11
Step-by-step explanation:
Set your formula as follow:
2x+3=3x-1 -> 2x+3-3x=-1 -> -x+3 = -1 -> -x=-4 -> x=4
now substitute x for 4 in the following
y-2=2(4)+1 -> y-2=8+1 ->y-2 = 9y -> y=11