- 3 ( n + 5 ) = 12

Mathematics

1 answer:

scZoUnD [109]3 years ago

6 0

Answer:the 1st one is N=17

THE SECOND ONE IS X=35

Step-by-step explanation:

hope this helps

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At the movie theatre, child admission is $5.70 and adult admission is $9.75 . On Friday, 173 tickets were sold for a total sales

storchak [24]

Answer: 94 child tickets

Step-by-step explanation:

Let x represent child tickets

Let y represent adult tickets

Cost Equation: 5.70x + 9.75y = 1306.10

Quantity Equation: x + y = 173

Solve the system of equations using the elimination method:

Multiply the Quantity Equation by -5.70

5.70x + 9.75y = 1306.10

-5.70x - 5.70y = -986.10

4.05y = 320.00

÷4.05 ÷4.05

y = 79

x + y = 173

x + 79 = 173

x = 94

7 0

3 years ago

I need you to answer with a, b, c, d

solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

$\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}$

For the given function:

$f(x)=2x^2-10x-3$ $x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}$ $x=\frac{10\pm\sqrt[]{100+24}}{4}$ $\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\ \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\ \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\ \end{gathered}$ $\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\ \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}$ $\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\ \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}$

Then, the zeros of the given quadratic function are: