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klasskru [66]
2 years ago
12

Absolute zero is what temperature on the fahrenheit scale?

Chemistry
1 answer:
vampirchik [111]2 years ago
8 0

Answer:

  • Absolute zero is - 459.67 °F

Explanation:

<u>1) Convert absolute zero to celsius:</u>

  • 0 K = - 273.15°C ( this is per definition of the scale)

<u>2) Convert - 273.15°C to Fahrenheit:</u>

  • T (°F) = T (°C) × 1.8 + 32 (this is the conversion equation=

  • T (°F) = - 273.15 × 1.8 + 32 = - 459.67 °F ← answer

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During the combustion of 2.00 g of coal, the temperature of 500 g of water inside the calorimeter increased from 25.0°c to 43.7°
pantera1 [17]
Answer is: 39,083kJ.
m(coal) = 2,00g.
m(water) = 500g.
ΔT = 43,7°C - 25°C = 18,7°C, <span>difference at temperatures.</span>
c(water) = 4,18 J/g·°C, <span>specific heat of water
</span>Q = m(water)·ΔT·c(water), heat of reaction.
Q = 500g·18,7°C·4,18J/g·°C.
Q = 39083J = 39,083kJ.
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3 years ago
A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif
slavikrds [6]

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c = specific heat of metal= ?

186.75 J=19 g\times c\times (175^oC-35^oC)

c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}

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