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Talja [164]
3 years ago
13

What is the standard measurement for gas pressure in atm?

Chemistry
1 answer:
ladessa [460]3 years ago
8 0

Answer:

1atm

Explanation:

1 atm =760 torr

1 atm = 10^5 pascal

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A car travels at 35.0 mi/hr. How far has it gone in 2455 seconds?
Vika [28.1K]

Answer:

<h3>The answer is 23.8 miles</h3>

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

<h3>distance = velocity × time</h3>

From the question

velocity = 35.0 mi/hr

time = 2455 s = 0.68 hr

We have

distance = 35 × 0.68

We have the final answer as

<h3>23.8 miles</h3>

Hope this helps you

5 0
3 years ago
What will happen to the pH of a buffer if acid/base ratio is increased by 100?
sp2606 [1]

Answer:

It will decrease by 2 units.

Explanation:

The Henderson-Hasselbalch equation for a buffer is

pH = pKa + log(base/acid)

Let's assume your acid has pKa = 5.

(a) If the base: acid ratio is 1:1,

pH(1) = 5 + log(1/1) = 5  + log(1) = 5 + 0 = 5

(b) If the base: acid ratio is 1:100,

pH(2) = 5 + log(1/100) = 5  + log(0.01) = 5 - 2 = 3

(c) Difference

ΔpH = pH(2) - pH(1) = 5 - 3 = -2

If you increase the acid:base ratio to 100:1, the pH will decrease by two units.

4 0
3 years ago
Laura sees a horse pulling a buggy.
Tcecarenko [31]

Answer:

B

Explanation:

I think that the anserw is B.

4 0
2 years ago
Total number of atoms in 4so2​
Sunny_sXe [5.5K]

Answer:

10

s=8

o=2

Hope it helps to

3 0
3 years ago
A particular graduated cylinder contains 24.0 mL Br2(liquid). The density of bromine at 25 degrees C is 3.12g/cm^3. Note that in
motikmotik

Answer:

2.82x10^{23}molecules

Explanation:

Hello.

In this case, given the volume (1cm³=1mL) and density of the bromine we are to firstly compute the mass since it will allow us to compute the representative particles:

\rho =\frac{m}{V}

m=\rho *V=3.12g/cm^3*24.0cm^3\\\\m=74.88gBr_2

Next, since the mass of one mole of diatomic bromine is 159.82 g (one bromine weights 78.91), we can next compute the moles in that sample:

n=74.88g*\frac{1mol}{159.82g} =0.469molBr_2

Finally, via the Avogadro's number we can compute the representative particles of bromine as follows:

particles=0.469mol*\frac{6.022x10^{23}molecules}{1mol}\\ \\2.82x10^{23}molecules

Best regards.

4 0
3 years ago
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