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Talja [164]
3 years ago
13

What is the standard measurement for gas pressure in atm?

Chemistry
1 answer:
ladessa [460]3 years ago
8 0

Answer:

1atm

Explanation:

1 atm =760 torr

1 atm = 10^5 pascal

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Porquê que o potássio é mais reativo que o cálcio? urgente!
saul85 [17]

Answer: O potássio possui apenas um elétron de valência. ... Considerando que o cálcio possui dois elétrons de valência, requer mais energia para a remoção de um elétron de valência. Devido a esse potássio, é mais reativo que o cálcio.

Explanation:

4 0
3 years ago
Draw the structure of an alkane or cycloalkane that has more than three but fewer than ten carbon atoms, and only primary hydrog
goldfiish [28.3K]

Answer:

The structures are shown in the figure.

Explanation:

The primary hydrogens are those which are attached to primary carbon.

Primary carbons are the carbons which are attached to only one carbon.

Primary carbons is bonded to three hydrogens.

In order to draw such structure we will draw structures which will have carbon with three hydrogens or no hydrogens (quaternary)

The structures are shown in the figure with clear marking.

7 0
2 years ago
The image below shows two nitrogen atoms. For these two atoms to form a stable molecule, N2, how many electrons would have to be
maxonik [38]
There are six electrons in the covalent bonds.

Two N atoms would be :N:· + ·:N:
An N₂ molecule would be :N:::N: or :N≡N:
This gives each N atom an octet of eight electrons in its valence shell.

7 0
3 years ago
True or false: Fungi are able to carry out photosynthesis, similar to plants
QveST [7]

Answer:

false

Explanation:

7 0
2 years ago
Read 2 more answers
Estimate your de Broglie wavelength when you are running. (For this problem use h = 10^−34 in SI units and 1 lb is equivalent to
AlekseyPX

Answer:

A. your running speed 1.5 m/s

B. your mass 70 kg

C. your de Broglie wavelength 6.32x10^{-36}m

Explanation:

Hello there!

In this case, since the equation for the calculation of the Broglie wavelength is:

\lambda =\frac{h}{m*v}

We can assume a running speed of about 1.5 m/s and a mass of 70 kg, so the resulting Broglie wavelength is:

\lambda =\frac{6.626x10^{-34}kg\frac{m}{s} }{70kg*1.5\frac{m}{s} }\\\\\lambda =6.32x10^-36m

Best regards!

7 0
3 years ago
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