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vaieri [72.5K]
3 years ago
15

Iron has a density of 7.86 g/cm3 (1 cm3=1 mL). Calculate the volume (in dL) of a piece of iron having a mass of 3.26 kg . Note t

hat the density is provided in different units of volume and mass than the desired units of volume (dL) and the given units of mass (kg). You will need to express the density in kg/dL (1 cm3 = 1 mL) before calculating the volume for the piece of iron.
Chemistry
1 answer:
Mkey [24]3 years ago
7 0
d=7,86\frac{g}{cm^{3}}=7,86\frac{0,001kg}{0,01dL}=0,786\frac{kg}{dL}\\
m=3,26kg\\\\\\
d=\frac{m}{V} \ \ \ \ \Rightarrow \ \ \ \ V=\frac{m}{d}=\frac{3,26kg}{0,786\frac{kg}{dL}}\approx4,15dL
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A balloon is filled with 0.75 L of Helium gas at 35 °C. If the temperature is increased to 113 °C, what thewill new volume be?
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Answer: 0.9398 Liters

Explanation:

Charles' Law

V1/ T1 = V2/T2

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Answer:

1. 136 °C.

2. 0.21 atm.

Explanation:

1. Determination of the new temperature in °C.

Initial volume (V1) = 1.35L

Final volume (V2) = 1.95L

Initial temperature (T1) = 283 K

Final temperature (T2) =...?

Using the Charles' law equation, the new temperature of the gas can be obtained as follow:

V1 /T1 = V2 /T2

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Finally, we shall convert 409 K to °C. This can be obtained as follow:

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Therefore, the new temperature of the gas is 136 °C.

2. Determination of the new pressure.

Initial pressure (P1) = 1.34 atm

Initial volume (V1) = 267 mL

Final volume (V2) = 1.67 L

Final pressure (P2) =.?

Next, we shall convert 1.67 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

1.67 L = 1.67 L × 1000 mL / 1 L

1.67 L = 1670 mL

Therefore, 1.67 L is equivalent to 1670 mL.

Finally, we shall determine the new pressure of the gas as follow:

Initial pressure (P1) = 1.34 atm

Initial volume (V1) = 267 mL

Final volume (V2) = 1670 mL

Final pressure (P2) =.?

P1V1 = P2V2

1.34 × 267 = P2 × 1670

357.78 = P2 × 1670

Divide both side by 1670.

P2 = 357.78 / 1670

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Therefore, the new pressure of the gas is 0.21 atm.

3 0
3 years ago
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Wewaii [24]

Answer:

The total amount of heat released  is  68.7 kJ

Explanation:

Given that:

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Q3 = - 94 x 2.09 x 30

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Total heat = Q1 + Q2 + Q3  = -31.43 kJ  + (-31.35 kJ  ) + (-5.894 kJ )  = -68.7 kJ

Total heat released = -68.7 kJ

Note that the "negative sign" simply indicates heat released, therefore no need to put it in the answer.

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