Answer:
Density = 8.92 g/cm³
Explanation:
Density shows the relation of the mass and volume of a determined object. We have this deffinition:
Density = mass / volume
First of all, we calcualte the volume of the block of copper metal, with the data given:
8.4 cm . 5.5 cm . 4.6 cm = 212.52 cm³
Now we replace at the density formula:
Density = 1896 g /212.52 cm³ = 8.92 g/cm³
First one would be amplitude second one up would be crest third one down would be the trough last one left is the wave length
Answer:
P (H₂) = 741 torr
Explanation:
Let's begin by listing out the given parameters:
Temperature (water) = 298 K, volume = 45.6 mL,
atmospheric pressure, P (total) = 765 torr, vapor pressure of water, P (H₂O) = 24 torr
To get the pressure of inside the tube, P (H₂), we apply Dalton's Law of Partial Pressure and we have:
P (total) = P (H₂) + P (H₂O)
P (total) = 765 torr, P (H₂O) = 24 torr
P (H₂) = P (total) - P (H₂O) = 765 - 24
P (H₂) = 741 torr
It therefore becomes clear that the pressure of H₂(g) is 741 torr
Answer:
11.58 L of N₂
Explanation:
We'll begin by calculating the number of mole in 37.2 g of magnesium. This can be obtained as follow:
Mass of Mg = 37.2 g
Molar mass of Mg = 24 g/mol
Mole of Mg =?
Mole = mass /Molar mass
Mole of Mg = 37.2 / 24
Mole of Mg = 1.55 moles
Next, we shall write the balanced equation for the reaction. This is illustrated below:
3Mg + N₂ —> Mg₃N₂
From the balanced equation above,
3 moles of Mg reacted with 1 mole of N₂.
Therefore, 1.55 moles of Mg will react with = (1.55 × 1)/3 = 0.517 mole of N₂
Thus, 0.517 mole of N₂ is need for the reaction.
Finally, we shall determine the volume of N₂ needed for the reaction as follow:
Recall:
1 mole of a gas occupies 22.4 L at STP.
1 mole of N₂ occupied 22.4 L at STP.
Therefore, 0.517 mole of N₂ will occupy = 0.517 × 22.4 = 11.58 L at STP
Thus, 11.58 L of N₂ is needed for the reaction.
