Well first you multiply 5 times 3 which is 15 then you add 4 which is 19 and 19 times 3 is 57 57-5 is 52
Answer:
or 2.738
Step-by-step explanation:
Let’s just look at the triangle on the top with the 
on the top and x on the bottom. (Basically the top half to the equilateral triangle)
There is a small square in the bottom right corner, which indicates that this triangle is a right triangle. This means that we can use the Pythagorean Theorem: 
We know that \sqrt{10} is our hypotenuse, and therefore our c in our equation. Let’s say that x=a in our equation. Therefore we are left to find b. However, b is half the length of the side of the original equilateral triangle. An equilateral triangle means that all three sides are the same length. Therefore our side would also be \sqrt{10} units long. However we know that b is half of that value, so b=
or 
Plugging these values into the equation:
x^2+ (\frac{\sqrt{10} }{2})^{2}=\sqrt{10} ^{2}
This approximately equals 2.738
We can see that the 33 degrees corresponds to angle A (parallel lines) meaning they’re equal.
This means that 33 + 2x = 5x (5x is the exterior angle, so the other two interior angles’ sum must equal to it)
3x = 33
x = 11
<span>It is: 7 to the power of 5 = 16807</span>
Answer:
3x-5> 6x- 14
Step-by-step explanation:
Let the blue ribbons be denoted by the letter x.
Then according to the given condition
3 times the blue ribbons = 3x
Decreased by 5 = 3x-5
is greater than
6 times the blue ribbons = 6x
decreased by 14 = 6x-14
Putting in one line
3x-5> 6x- 14
Solving the inequality
3x-5> 6x- 14
Taking both sides positive as in modulus
14-5 > 6x-3x
9> 3x
9/3 > x
3> x
Again solving for inequality
3x-5> 6x- 14
Taking one side negative that is mod
3x-5> -6x + 14
3x+ 6x > 14+5
9x> 19
x > 19/9
x > 2.11
so x lies between 2 and 3
3 > x > 2.11
Now putting the values for x= 19
3x-5> 6x- 14
57-5> 114-14
52 > 100 False
Now putting the values for x= 3
3x-5> 6x- 14
9-5> 18-14
4>4 False
Now putting the values for x= 2
3x-5> 6x- 14
6-5> 12-14
1> -2 True
There are 2 blue ribbons
