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Nikitich [7]
3 years ago
9

How do you solve a=3n+1

Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0
Can you be more specific? Do I find or simplify?
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If m = 5 and n = -2, evaluate 3m - 4n and n2 - m and find the product of the two expressions.
ddd [48]

Hence the correct answer is C) -23

Further explanation:

We have to put the values of m and n into both expression first separately and then multiply the answers.

Given expressions are:

Exp\ 1:3m-4n\\Exp\ 2: n^2-m

The values are:

m=5\\n=-2

Putting the values in expression 1:

3m-4n\\=3(5)-4(-2)\\=15+8\\=23

Putting the values of m and n in second expression

n^2-m\\=(-2)^2-5\\=4-5\\=-1

Multiplying both expressions:

(3m-4n)(n^2-m)=23* (-1)=-23

Hence the correct answer is C) -23

Keywords: Polynomials, Putting values in expressions

Learn more about polynomials at:

  • brainly.com/question/4142886
  • brainly.com/question/4934417

#LearnwithBrainly

8 0
3 years ago
Write an equation in point slope form that represents the line that passes through the point (-2,-1) and has a slope of 5. Then,
jeka57 [31]
Point-slope equation=y+1=5(x+2)
slope intercept form=5x+9
8 0
3 years ago
I don't get the problem
Ulleksa [173]
A(b + c) = a*(b + c) = a*b + a*c

You must multiply individual terms and see what it would equal
3 0
3 years ago
PLS HELPP I WILL MARK BRAINLIEST!!
Tpy6a [65]
The answer is 2 first you add then multiple
8 0
3 years ago
Read 2 more answers
Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this
Firlakuza [10]
The amount of substance left of a radioactive element of half life, t_{\frac{1}{2}} after a time, t, is given by:

N(t)=N_0\left( \frac{1}{2} \right)^ \frac{t}{t_{  \frac{1}{2} }}

Given that <span>potassium-40 has a half life of approximately 1.25 billion years.

The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

0.1=100\left( \frac{1}{2} \right)^ \frac{t}{1.25}} \\  \\ \Rightarrow\left( \frac{1}{2} \right)^ \frac{t}{1.25}}=0.001 \\  \\ \Rightarrow\frac{t}{1.25}\ln\left( \frac{1}{2} \right)=\ln(0.001) \\  \\ \Rightarrow \frac{t}{1.25}= \frac{\ln(0.001)}{\ln\left( \frac{1}{2} \right)} =9.966 \\  \\ t=9.966(1.25)=12.5

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is 12.5 billion years.</span>
3 0
3 years ago
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