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3 years ago

Chau's shop sells quarts of ice cream each day. How much is this in pints?

Mathematics

1 answer:

barxatty [35]3 years ago

5 0

Answer:

One quart is 2 pints

Step-by-step explanation:

multiply the number of quarts by 2 to get the number of pints.

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What’s the answer plz help ?

guajiro [1.7K]

Answer: 452.16 or just 452 units^3

Step-by-step explanation:

V= πr^2*h

using 3.14 like the problem asks could effect what you're rounding to but either way pi(6)^2=113.04 *4= 452.16

7 0

3 years ago

Read 2 more answers

Score Frequency

RUDIKE [14]

Scores on an AP Exam at a local high school are recorded in the table. What was the average score?

Answer: D) 4.266 is correct

Explanation:

We are given the below frequency table:

Score Frequency

1 | 0

2 | 3

3 | 4

4 | 16

5 | 22

Let's denote the score by $x$ and frequency by $f$ .

The average formula is:

$Average=\frac{\sum fx}{\sum f}$

$=\frac{(1\times0) + (2\times3)+(3\times4) +(4\times16) + (5\times22)}{0+3+4+16+22}$

$=\frac{0+6+12+64+110}{45}$

$=\frac{192}{45}=4.267$

Therefore, the average score was 4.267

Hence the option D) 4.266

7 0

3 years ago

Help pls .!!!!!!!!!!!

Igoryamba

A and C are the answer

4 0

2 years ago

Read 2 more answers

Carlie is out shopping and finds a 198.00 hat that is on sale for 90% of its original price. What is the new cost of the item? C

lbvjy [14]

I believe the new cost of the item is $19.80

5 0

2 years ago

In a survey at a local college, 18% of students reported that they do not own a mobile device with internet capabilities. if 20

Sholpan [36]

Answer:

0.64

Step-by-step explanation:

The probability that randomly selected student doesn't own a mobile device with internet capabilities is $p=0.18$ and the probability that randomly selected student owns a mobile device with internet capabilities is $q=1-p=1-0.18=0.82.$

If 20 students are selected at random, the probability that at most 5 students (0 students, 1 student, 2 students, 3 students, 4 students or 5 students) don't own a mobile device with internet capabilities is

$Pr=C_{20}^0p^0q^{20}+C_{20}^1p^1q^{19}+C_{20}^2p^2q^{18}+C_{20}^3p^3q^{17}+C_{20}^4p^4q^{16}+C_{20}^5p^5q^{15}=q^{20}+20pq^{19}+190p^2q^{18}+1,140p^3q^{17}+4,875p^4q^{16}+15,504p^5q^{15}\approx 0.6405021423\approx 0.64.$

3 0

2 years ago