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Salsk061 [2.6K]
3 years ago
8

A school wishes to accept 2000 students for their freshman class, and they expect 20,000 applications. In order to make their ad

missions decisions very easy, the only criterion they will use is SAT score. So, their goal is to accept a student if and only if their SAT score is in the top 10%. However, because their computer system is so old, the applications only come in one at a time, and they must decide whether to accept or reject before moving on to the next application. Assuming that SAT scores are normally distributed with a mean of 1000 and a standard deviation of 200, how should they set the score threshold to end up with as close to 2000 students as possible? Give your answer first symbolically (in terms of a pdf, cdf, etc), then use a normal distribution table1 to provide a numerical answer.
Mathematics
1 answer:
vovangra [49]3 years ago
3 0

Answer:

456

Step-by-step explanation:

Let X be the SATscore scored by the students

Given that X is normal (1000,200)

By converting into standard normal variate we can say that

z=\frac{x-1000}{200} is N(0,1)

To find the top 10% we consider the 90th percentile for z score

Z 90th percentile = 1.28

X= 200+1.28(200)\\= 200+256\\=456

i.e. only students who scored 456 or above only should be considered.

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Nikitich [7]

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61

Step-by-step explanation:

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2 years ago
Help me!<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7B84%7D%20%2B%5Csqrt%7B84%7D%20%3D%3F" id="TexFormula1" title="\sqrt{84}
lukranit [14]

Answer:

18.4

Step-by-step explanation:

Well the square root of 84 isn't an exact answer.

But when rounded it equals to approximately 9.16 or rounded even more 9.2 at most.

So 9.2 + 9.2 = 18.4.

So the answer is ≈ 18.4

Have a good day or night wherever you are. May GOD Bless You!!

8 0
2 years ago
1.935 people visit a library during one week.
d1i1m1o1n [39]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
A toy rocket is launched straight up into the air with an initial velocity of 60ft/s from a table 3 ft above the ground. If acce
Sav [38]
For this case we have the following equation:
 h (t) = at ^ 2 + v * t + h0
 Substituting values we have:
 h (t) = - 16 * t ^ 2 + 60 * t + 3
 We equate the equation to zero:
 -16 * t ^ 2 + 60 * t + 3 = 0
 We look for the roots of the polynomial:
 t1 = -0.04935053979258153
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option 3
5 0
4 years ago
A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between their areas is 40 squ
katrin [286]

Let us assume side length of a square sign = x feet.

Side of the square poster is 2 feet less than the sides of a square sign.

Therefore, side of the square poster in terms of x is =  (x-2) feet.

Given the difference between their areas is 40 square​ feet.

We know, area of a square = (side)^2.

Therefore, we can setup an equation,

(Square sign side length)^2 -  ( square poster side length)^2 = 40.

(x)^2 - (x-2)^2 = 40.

Expanding (x-2)^2 = x^2 +(2)^2 -2(x)(2) = x^2 + 4 - 4x, we get

x^2- (x^2 + 4 - 4x ) = 40.

Distributing minus sign over parenthesis, we get

x^2 -x^2 -4 +4x =40.

Combining like terms, x^2-x^2=0, we get

0-4+4x=40.

-4 +4x =40.

Adding 4 on both sides, we get

-4 +4 +4x =40+4.

4x = 44.

Dividing both sides by 4.

4x/4 = 44/4.

x= 11.

Therefore,  side length of a square sign = 11 feet.

The square poster is 2 feet less than the sides of a square sign.

2 less than 11 is 11-2 = 9 feet.

Therefore, the square poster is 9 feet.



6 0
3 years ago
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