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Vaselesa [24]
3 years ago
12

PLEASE HELP ME GET THIS DONE

Mathematics
1 answer:
Grace [21]3 years ago
4 0

Answer:

C

Step-by-step explanation:

The line on the left has equation y = x - 2

The start of the line has an open circle at x = 3 meaning that x ≠ 3

The line is defined as y = x - 2 for x < 3

The line on the right has equation y = x - 1

The start of the line has a closed circle at x = 3 meaning that x can equal 3

The line is defined as y = x - 1 for x ≥ 3

Thus the definition of the function is C

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Find the surface area of square pyramid someone help
IgorC [24]

Answer:

65 square units

Step-by-step explanation:

The base of the pyramid is 5 by 5 , surface area is 25 square units.

the side of each one is 4 units "high" and 5 long at the base and to find the are of a triangle you multiple base times height then dived by 2. Therefore each side of the triangle is 10 units square. You have 4 sides so...

40 (total of all the sides ) +25 ( base ) = 65

4 0
3 years ago
Hello need help please with Divide rational and simplify
aliina [53]
Dividing fractions is the same as multiplying by its reciprocal so you can change the equation to this
\frac{ - 14 + 7x}{4}  \times  \frac{4}{4 - 2x}
And you can simplify by eliminating the fours and multiplying straight across
\frac{ - 14 + 7x}{4 - 2x}
You can pull out - 7 from the top and 2 from the bottom so you have this
\frac{ - 7(2  -  x)}{2(2 - x)}
And then you can cancel out to (2-x) to get an answer of
\frac{ - 7}{2}
5 0
3 years ago
Pleaseeee helppp i’m running out of time
PilotLPTM [1.2K]

Answer:

Square Root of 162 ~ 12.727

Step-by-step explanation:

Simply do the Pythagorean Theorem!

a^2 + b^2 = c^2

This case we're solving for the long side which is the hypothenuse.

9^2+9^2= c^

81+81=c^

162=c^

Square root of 162

Which is 12.727

3 0
2 years ago
Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet
Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\

Take the second derivative of the function, to check if it will given a minimum perimeter

\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)

Determine the critical points of the first derivative;

df/dw = 0

\frac{-324}{w^2} +2 = 0\\\\-324 + 2w^2=0\\\\2w^2 = 324\\\\w^2 = \frac{324}{2} \\\\w^2 = 162\\\\w= \sqrt{162}\\\\w = 12.728 \ m

L = 162 / 12.728

L = 12.728 m

Therefore, the width and length of rectangle is 12.728 m

3 0
3 years ago
TOY has coordinates T (-3, 4), O (-4, 1) and Y (-2, 3). a translation maps point T to T' (-1, 1). find the coordinates of O' and
NeX [460]

Answer:

Answer:  The correct option is (A) O' (−2, −2); Y' (0, 0).

Step-by-step explanation:  Given that the co-ordinates of the vertices of ΔTOY are T(−3, 4), O (−4, 1), and Y (−2, 3). A translation maps point T to T' (−1, 1).

We are to find the co-ordinates of the points O' and Y'.

The given transformation from T to T' is

T(−3, 4)   ⇒   T' (−1, 1).

Let,  (−3 + x, 4 + y) =  (-1, 1).

So,

and

That is, the transformation rule is

(a, b) ⇒ (a+2, b-3).

Therefore,

co-ordinates of O' are (-4+2, 1-3) = (-2, -2),

and

co-ordinates of Y' are (-2+2, 3-3) = (0, 0).

Thus, the required co-ordinates of O' and Y' are (-2, -2) and (0, 0) respectively.

Option (A) is correct.

8 0
3 years ago
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