Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2
Area of semicircle:
A = 1/2 π r^2 = 1/2 π 6^2 = 18<span>π m^2
Area of figure = </span>Area of semicircle + Area of Triangle
Area of figure = 18π + 30 m^2
Answer is C.
18π + 30 m^2
the standard equation of the circle having the given center and radius is 
.
I'm pretty sure the answer is 4 because, 4*21= 84.
S = 2J - 1
R = J + 53
S - 25 = J + 25...S = J + 50
2J - 1 = J + 50
2J - J = 50 + 1
J = 51 <===Jason has 51 CD's
R = J + 53
R = 51 + 53
R = 104 <===Raoul has 104 CD's
S = 2J - 51
S = 2(51) - 1
S = 102 - 1
S = 101 <===Seth has 101 CD's
Answer:
i think the answer is 76cm im pretty sure it is
Step-by-step explanation:
if so mark this as brainliest answer!!!
