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Salsk061 [2.6K]
3 years ago
11

How many times as great as 10% is 100%?

Mathematics
2 answers:
monitta3 years ago
8 0

It is 10 times greater because

10x10=100


Aneli [31]3 years ago
4 0
10 times greater because 10 times 10
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Which of the following correctly represent the commutative property?
Ira Lisetskai [31]
The bottom one



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7 0
3 years ago
Read 2 more answers
-1.2x + 11.45 = 8.21
kondaur [170]
Hi there!

If you solve for x in this problem you would end up with a result of \boxed{x = 2.7}. To find x you need do the following:

First, subtract 11.45 from both sides:

-1.2x+11.45-11.45=8.21-11.45

-1.2x=-3.24

Next, divide both sides by -1.2:

\frac{-1.2x}{-1.2} = \frac{-3.24}{-1.2}

To get the end result of:

\boxed{x = 2.7}

-Your friend, ASIAX
7 0
3 years ago
I don’t know it tried solving it but couldn’t find it
Hitman42 [59]

8f - 25 = 47. Add 25 to both sides.

8f = 72. Divide each side by 8.

f = 9.

4 0
3 years ago
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Hello can you please help me posted picture of question
MAXImum [283]
The answer is Letter C - 1/2,775

The probability of choosing one of them is 2 out of 75 while the probability of choosing the other one is 1 out of 74. 74 band members, not counting the other person (you or your bother).
 
Computation:
P = 2 / 75 * 1 / 74
   = 0.0266... * 0.01351...
   = 1 / 2,775
You can also multiply 75 with 74 to get a total of 5,550 then divide it by 2 students to be selected to get 2,775. Meaning one out of 2,775 possibilities.
8 0
3 years ago
A = √7 + √c and b = √63 + √d where c and d are positive integers.
mrs_skeptik [129]

Answer:

\displaystyle a:b=\frac{1}{3}

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]

b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]

\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]

From [3]:

9c=d

Replacing into [2]:

b=\sqrt{63}+\sqrt{9c}

We can express 63=9*7:

b=\sqrt{9*7}+\sqrt{9c}

Taking the square root of 9:

b=3\sqrt{7}+3\sqrt{c}

Factoring:

b=3(\sqrt{7}+\sqrt{c})

Find the ration a:b:

\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}

Simplifying:

\boxed{a:b=\frac{1}{3}}

3 0
3 years ago
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