Answer:
4/5 of the cattle is left
Step-by-step explanation:
Given,
A farmer sells 2/5 of his cattle
Let "x" be the total number of cattle
Then,
sold = 2 / 5 x
Then,
Remaining = x - 2x / 5
remaining = 3x / 5
He gives 1/3 of the remainder to his son
son = 1 / 3 × 3x / 5
son = x / 5
Then,
Remaining = 3x / 5 - x / 5
Remaining = 4x / 5
Hope this answer helps you :)
Have a great day
Mark brainliest
Thus 4/5 of the cattle is left
1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)
When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)
2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;
A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)
Answer:
Step-by-step explanations:
Hi love ,
So the terms is :
<u>-80 , 5p , -8z </u>
and the coefficients is :
<u>5 , -8</u>
<u>Thank you :)</u>
<u></u>
