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3 years ago

9

The castle's gate is open 18 hours a day and must be guarded. Five knights are ordered to split each day’s guard duty equally. H

ow long will each knight spend on guard duty in one day?
Record your answer in hours.

1 answer:

Lubov Fominskaja [6]3 years ago

3 0

The answer is 3.5 hours.
18 hours divided by 5 knights.

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The cost, c(x), for a taxi ride is given by c(x) = 2x + 2.00, where x is the number of minutes.

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2 years ago

___________ is a standard of measure for a physical quantity and is included as part of the x and y axes labels on a line graph.

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Answer:

Unit of measure

Step-by-step explanation:

Unit of measure

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3 years ago

It is based on ratios

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Answer:

Gianna makes $18 per hour.

Step-by-step explanation:

Given Gianna makes 90$ for 5 hours. That means she should make $\frac{90}{5}$ $ = 18$ every hour.

Therefore we have:

a.

HOURS DOLLARS

1 18

2 36

3 54

4 72

5 90

6 108

7 126

b.

For the tabular column mark Hours on the x - axis and Dollars on the Y - axis. It can be plotted from the above table easily.

c.

If Gianna works for 8 hours she would have made 8 X 18 = 144$.

So, she will earn 144$ in 8 hours.

d.

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3 years ago

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Check al

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Let's rewrite each equation in the Slope-Intercept Form of the Equation of a Line. First, let's start with the main equation:

$\bullet \ 5x-2y=-6 \therefore y=\frac{5}{2}x+3$

Then, our options are the following:

$A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \therefore y=-\frac{2}{5}x-2 \\ \\ C) \ 2x-5y=-10 \therefore y=\frac{2}{5}x+2 \\ \\ D) \ y+4=-\frac{2}{5}(x-5) \therefore y=-\frac{2}{5}x-2 \\ \\ E) \ y-4=\frac{5}{2}(x + 5) \therefore y=\frac{5}{2}x+\frac{33}{2}$

For two perpendicular lines it is true that the product of its slopes is:

$m_{1}m_{2}=-1$

$m_{1}m_{2}=-1 \\ \\ m_{1} \ is \ the \ slope \ of \ y=\frac{5}{2}x+3, \ that \ is, \ m_{1}=\frac{5}{2} \\ \\ Then, \ the \ slope \ of \ a \ perpendicular \ line \ is: \\ \\ m_{2}=-\frac{2}{5}$

According to this, only A) B) and D) might be the perpendicular lines we are looking for. Notice that these lines are the same. The other condition is that the line must pass through the point (5, -4). By substituting this point in the equation, we have:

$y = -\frac{2}{5}x-2 \\ \\ -4=-\frac{2}{5}(5)-2 \\ \\ -4=-2-2 \\ \\ \boxed{-4=-4} \ True!$

Finally, the right answer are:

$A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \\ \\ D) \ y+4=-\frac{2}{5}(x-5)$

8 0

2 years ago

Read 2 more answers