A Punnett square would help here.
Let's say (R) is dominant red and (r) is recessive red, aka yellow.
You start with F1 hybrid flowers that are all (Rr) - these are all <em>orange</em>. So when they reproduce, both parents are (Rr). When you create a Punnett square, you'll see that the results for the F2 generation are (RR), (rr), and (Rr) twice.
(RR) is red, (rr) is yellow, and (Rr) is orange, just like the F1 generation.
Answer:
The correct answer is c. 3/16.
Explanation:
In the given question two traits being studied, the traits are flower color and seed shape.
This is a typical Mendel’s dihybrid cross. According to the question purple colour (P) and round seed (R) are dominant traits.
When heterozygous purple-flowered (Pp), round-seeded (Rr) individuals are crossed, four different types of plants are produced phenotypically in the ratio 9:3:3:1.Out of 16 offspring, 9 are purple flowered, round seeded pea plants, 3 pea plants are white-flower with round seed, 3 are purple- flower with wrinkled seed and 1 pea plant is white-flowered with wrinkled seed pea plant is produced.
What? no. B. false, cooled magma is called extrusive igneous rock.
