Answer:
Bacteria that are oxidase-negative may be anaerobic, aerobic, or facultative; the oxidase negative result just means that these organisms do not have the cytochrome c oxidase that oxidizes the test reagent. They may respire using other oxidases in electron transport.)
<span> Basically the male will have CC, the hen will have cc, and neither of them will have I. The key thing is that _all_ the chicks are coloured.
The male must have at least 1 C to be coloured, and cannot possess the dominant I. The hen has cc and/or an I to not be coloured.
That one chick is coloured would tell you little - only that the hen couldn't have 2 inhibitor alleles because otherwise the chick would have to have one and it doesn't.
However, for all of many chicks to be coloured, that means that the hen can't have any inhibitor alleles (otherwise around 50% would be white for that reason alone).
So to be colourless, the hen must be cc. However, if the male had only 1 colour allele (ie it was Cc) that would still mean that 50% of the chicks would be Cc (daddy's 'c' and one of mummy's 'c's).
Hope this helps please award brainly :)
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Answer:
1) What kind of organisms have this organelle?
->eukaryotic
2)What is the name of the organelle?
->mitochondria
3)Reactants
->oxygen, glucose
4)Products
->carbon dioxide, water, ATP
5)Energy source
->glucose
hope this helps :)
Answer:
Option A (mediate...........polypeptides) would be the appropriate choice.
Explanation:
- That's only because the leucine zipper symbol consisting of such a leucine remnant anywhere certain 7th point and has an α helical attachment.
- Maybe the leucine including its zipper between one protein dimples again from α-helix as well as interdigit this same leucine including its iterator of some other antibody.
Some other possibilities in question are not connected to something like the situation in question So that is the correct approach.
