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3 years ago

What is possible reason for trial b not obeying the law of conservation of mass

Chemistry

2 answers:

IRISSAK [1]3 years ago

3 0

The answer is D.)The balloon-like device was not used in this trial.

laiz [17]3 years ago

3 0

Answer:

D: The balloon-like device was not used in this trial

Explanation: The balloon-like device was not used in this trial. Therefore, some CO2 gas escaped and was not measured.

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f an electron has a mass of 9.709 x 10-31 kg, and a proton has a mass of 1.672 x 10-27 kg, approximately how many electrons are

VikaD [51]

Answer:

The answer is 1722 e⁻

Explanation:

Let's make a rule of three:

9.708×10⁻³¹ kg is the mass of 1 e⁻

1.672 ×10⁻²⁷ kg (which is 1 p⁺), how many e⁻ does it contain.?

1.672 ×10⁻²⁷ kg / 9.708×10⁻³¹ kg

The answer is 1722 e⁻

3 0

4 years ago

What is CdF^4 compound name

topjm [15]

Answer:

well it might be 1.)Cadmium Fluoride CdF2 150.4078

2.)Cadmium(II) Perfluorate Cd(FO4) 2278.403

3.)Cadmium Ferrocyanide Cd2Fe(CN) 6436.7714

Explanation:

3 0

3 years ago

(Please!!!) Which of the following is not an example of kinetic energy? (2 points) sound chemical energy radiant energy heat

boyakko [2]

Answer:

heat

Explanation:

7 0

4 years ago

If a compound has a composition of 82% nitrogen and 18% hydrogen, what is the empirical formula for this compound

Damm [24]

Answer: The empirical formula for the given compound is $NH_3$

Explanation : Given,

Percentage of H = 18 %

Percentage of N = 82 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 18 g

Mass of N = 82 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{18g}{1g/mole}=18moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{82g}{14g/mole}=5.8moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.8 moles.

For Hydrogen = $\frac{18}{5.8}=3.10\approx 3$

For Nitrogen = $\frac{5.8}{5.8}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : N = 3 : 1

Hence, the empirical formula for the given compound is $NH_3$

3 0

3 years ago

How many boron (B) and sulfur (S) atoms are in B253?

Kay [80]

Answer:

2 boron and 3 sulfur

Explanation:

The subscript/ number behind and under is a subscript this tells you how many atoms there are

5 0

3 years ago