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lions [1.4K]
3 years ago
6

How many boron (B) and sulfur (S) atoms are in B253?

Chemistry
1 answer:
Kay [80]3 years ago
5 0

Answer:

2 boron and 3 sulfur

Explanation:

The subscript/ number behind and under is a subscript this tells you how many atoms there are

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in an experiment magnesium ribbon was heated in air the product formed was found heavier than original ribbon.potassium manganat
AlladinOne [14]

Answer:

1: due to difference in reactivity and melting point

2 during the reaction both combine with oxygen in this case magnesium remain solid but some potassium vaporise

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3 years ago
The table below shows the electronegativity values of various elements on the periodic table. Electronegativities A partial peri
MatroZZZ [7]

Answer:

Oxygen and Chlorine

Explanation:

Covalent bonds involve the sharing of electrons between nonmetals.

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3 years ago
Read 2 more answers
What is the pOH of a 0.150 M solution of potassium nitrite? (Ka HNO2 = 4.5 x 10−4 )
yanalaym [24]

Answer:

11.9 is the pOH of a 0.150 M solution of potassium nitrite.

Explanation:

Solution :  Given,

Concentration (c) = 0.150 M

Acid dissociation constant = k_a=4.5\times 10^{-4}

The equilibrium reaction for dissociation of HNO_2 (weak acid) is,

                           HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+

initially conc.         c                       0         0

At eqm.              c(1-\alpha)                c\alpha        c\alpha

First we have to calculate the concentration of value of dissociation constant (\alpha ).

Formula used :

k_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}

Now put all the given values in this formula ,we get the value of dissociation constant (\alpha ).

4.5\times 10^{-4}=\frac{(0.150\alpha)(0.150\alpha)}{0.150(1-\alpha)}

4.5\times 10^{-4} - 4.5\times 10^{-4}\alpha =0.150\alpha ^2

0.150\alpha ^2+4.5\times 10^{-4}\alpha-4.5\times 10^{-4}=0

By solving the terms, we get

\alpha=0.0533

No we have to calculate the concentration of hydronium ion or hydrogen ion.

[H^+]=c\alpha=0.150\times 0.0533=0.007995 M

Now we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.007995 M)

pH=2.097\approx 2.1

pH + pOH = 14

pOH =14 -2.1 = 11.9

Therefore, the pOH of the solution is 11.9

4 0
3 years ago
Use Target Reading Skills After you read the section, reread the paragraphs that contain definitions of Key Terms. Use all of th
Ksju [112]
A_______________________
3 0
2 years ago
PLEASE HELP!
Anon25 [30]

Answer:

C. Mole

Explanation:

Chemical formula deals with mole number

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