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lions [1.4K]
2 years ago
6

How many boron (B) and sulfur (S) atoms are in B253?

Chemistry
1 answer:
Kay [80]2 years ago
5 0

Answer:

2 boron and 3 sulfur

Explanation:

The subscript/ number behind and under is a subscript this tells you how many atoms there are

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- Standard state refers to
yulyashka [42]

Answer: The standard state refers to 1 atm and 25^{o}C.

Explanation:

It is known that a chemical/substance can either be present in a solid, liquid or gaseous state.

So, when the phase of a substance like solid, liquid or gas is present at 1 atmosphere pressure and at a temperature of 25^{o}C then it known as standard state of substance.

Thus, we can conclude that standard state refers to 1 atm and 25^{o}C.

4 0
2 years ago
A hydrocarbon of pentane has two isomeric forms—n-pentane and iso-pentane. The molecular formula of the n-pentane is C5H12. Pred
Monica [59]
An iso pentane is an isomeric form of n-pentane. Isomers have same molecular formula but differ in the atomic arragement projected in 3D and the arrangement of atoms primarily resulting to a different set of properties. In this case, isopentane also has a molecular formula of an alkane <span>C5H12</span>
5 0
3 years ago
State Hess' law of constant heat summation.
AveGali [126]

Answer:

-74.6 kj/mol

Explanation:

you can see the answer at the pic

8 0
3 years ago
Anyone know how to hide a body asking for a friend
Wittaler [7]
Throw it in the ocean lol
4 0
2 years ago
Calculate the ph of a 0.20 m solution of kcn at 25.0 ∘c. express the ph numerically using two decimal places
storchak [24]
The pH of the solution is basically the negative logarithm of the concentration of hydrogen ions or H+. In equation form, pH = -log[H+]. It could also be in terms of the concentration of hydroxide ions or OH- as pOH, where pOH = -log[OH-]. The sum of pH and pOH is 14. These are the important equations to know when it comes to equilibrium pH problems.

KCN is a basic salt coming from the reaction of a weak acid, HCN, and a strong base, KOH. In the hydrolysis of KCN, only the strong conjugate base (SCB) is involved. Since HCN is the weak acid, the SCB is CN-. The reaction would be

CN- + H2O ⇔ HCN + OH-

The important data is the equilibrium constant of acidity of the weak acid. Ka for HCN is 6.2×10^-10. Then, let's do the ICE(Initial-Change-Equilibrium) analysis.

          CN-    +    H2O    ⇔    HCN +    OH-

I      0.2 m             ∞                   0             0
C      -x                 ∞                   +x        +x
-----------------------------------------------------------
E      0.2-x                               +x         +x

The value x denotes the number of moles CN- reacted. There is no value for H2O because the solution is dilute such that H2O>>>CN-. Then, we apply the ratio:

K_{H} = \frac{ K_{W} }{ K_{A} } = \frac{[HCN][OH-]}{[CN-]}

where K,H is the equilibrium constant of hydrolysis and Kw is equilibrium constant for water solvation which is equal to 1×10^-14. Therefore,

K_{H} = \frac{ 1x10^-14}{ 6.2x10^-10 } = \frac{[X][X]}{[0.2-X]}

x = 0.001788 m
Since the value of OH- is also x, then OH-=0.001788 m. Consequently,

pOH = -log(0.001788) = 2.75
pH = 14 - pOH = 14 - 2.75
pH = 11.25

4 0
3 years ago
Read 2 more answers
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