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3 years ago

How many boron (B) and sulfur (S) atoms are in B253?

Chemistry

1 answer:

Kay [80]3 years ago

5 0

Answer:

2 boron and 3 sulfur

Explanation:

The subscript/ number behind and under is a subscript this tells you how many atoms there are

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in an experiment magnesium ribbon was heated in air the product formed was found heavier than original ribbon.potassium manganat

AlladinOne [14]

Answer:

1: due to difference in reactivity and melting point

2 during the reaction both combine with oxygen in this case magnesium remain solid but some potassium vaporise

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3 years ago

The table below shows the electronegativity values of various elements on the periodic table. Electronegativities A partial peri

MatroZZZ [7]

Answer:

Oxygen and Chlorine

Explanation:

Covalent bonds involve the sharing of electrons between nonmetals.

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3 years ago

Read 2 more answers

What is the pOH of a 0.150 M solution of potassium nitrite? (Ka HNO2 = 4.5 x 10−4 )

yanalaym [24]

Answer:

11.9 is the pOH of a 0.150 M solution of potassium nitrite.

Explanation:

Solution : Given,

Concentration (c) = 0.150 M

Acid dissociation constant = $k_a=4.5\times 10^{-4}$

The equilibrium reaction for dissociation of $HNO_2$ (weak acid) is,

$HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+$

initially conc. c 0 0

At eqm. $c(1-\alpha)$ $c\alpha$ $c\alpha$

First we have to calculate the concentration of value of dissociation constant $(\alpha )$ .

Formula used :

$k_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}$

Now put all the given values in this formula ,we get the value of dissociation constant $(\alpha )$ .

$4.5\times 10^{-4}=\frac{(0.150\alpha)(0.150\alpha)}{0.150(1-\alpha)}$

$4.5\times 10^{-4} - 4.5\times 10^{-4}\alpha =0.150\alpha ^2$

$0.150\alpha ^2+4.5\times 10^{-4}\alpha-4.5\times 10^{-4}=0$

By solving the terms, we get

$\alpha=0.0533$

No we have to calculate the concentration of hydronium ion or hydrogen ion.

$[H^+]=c\alpha=0.150\times 0.0533=0.007995 M$

Now we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (0.007995 M)$

$pH=2.097\approx 2.1$

pH + pOH = 14

pOH =14 -2.1 = 11.9

Therefore, the pOH of the solution is 11.9

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3 years ago

Use Target Reading Skills After you read the section, reread the paragraphs that contain definitions of Key Terms. Use all of th

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A_______________________

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2 years ago

PLEASE HELP!

Anon25 [30]

Answer:

C. Mole

Explanation:

Chemical formula deals with mole number

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3 years ago