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Eva8 [605]
3 years ago
7

What is CdF^4 compound name

Chemistry
1 answer:
topjm [15]3 years ago
3 0

Answer:

well it might be 1.)Cadmium Fluoride CdF2 150.4078

2.)Cadmium(II) Perfluorate Cd(FO4) 2278.403

3.)Cadmium Ferrocyanide Cd2Fe(CN) 6436.7714

Explanation:

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it is A mark me big brain pls

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PbCl2s) + Cl2g -<br> + PbCl40)<br> ΔΗ = ?
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ichedgepeth

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beginner because it's tough than other things

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3 years ago
Briefly explain how magnetic behavior is related to the arrangement of valence electrons in the outer orbitals
olga nikolaevna [1]

Answer:

Elements with unpaired valence electrons in the outer orbital are paramagnetic. Elements that are predicted to exhibit paramagnetic behavior may exhibit ferromagnetic behavior. Elements that contain only paired valence electrons are diamagnetic.

3 0
3 years ago
What is the oxidation number of each atom in sodium hydrogen carbonate
Sati [7]

Answer:

Oxidation number of each atom in sodium hydrogen carbonate ( NaHCO3) are

Na = +1

H = +1

C = +4

O = -2

Explanation:

Let's pick the first atom

NaHCO3

find oxidation number of Na

Na + 1 +4 + 3(-2) = 0( because there is no charge)

Na + 5 - 6 = 0

Na = 6 -5

Na = +1

Always put the sign

Find the oxidation number of H in NaHCO3

+1 + H + 4 + 3(-2) = 0.

H + 1 + 4 + 3(-2) = 0

H + 5 -6 = 0

H = 6 -5

H = +1

Find the oxidation number of C In NaHCO3

+1 +1 +C + 3(-2) = 0

C + 1+1-6 = 0

C +2 - 6= 0

C = 6 -2

C = +4

Find the oxidation number of O in NaHCO3

+1 + 1 + 4 + 3(O) = 0

6 + 3 (O) = 0

3(O) = -6

Divide through by 3 to get O

3(O) / 3 = -6 / 3

O = -6/3

O = -2

8 0
3 years ago
What is the molality of a solution that contains 31.0 g HCl in 5.00 kg water? (molar mass of
dlinn [17]

Answer:

0.17M

Explanation:

5kg of water contains 5 liters as the density of water is 1000 kgm^{-3}

Therefore one liter of water contains 31/5=6.2g of HCl

Molality of the solution = 6.2/36.46 =0.17M

3 0
3 years ago
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