All categories

3 years ago

How big is earth compared to Jupiter

1 answer:

5 0

Jupiter has a diameter of about 88,695 miles (142,800 kilometers) which is more than 11 times the diameter of Earth. It’s volume is over 1,300 times the volume of Earth. This mean that Jupiter is so big that over 1,300 Earth could fit inside of it.

You might be interested in

There are 21 students in a class. The median age of the students is 23. The oldest student is 29.

Varvara68 [4.7K]

Answer:

1) At least one (the 11th) student is 23 (years old), <u>Must be true</u>

2) Some students are younger than 15 <u>Could be true</u>

Step-by-step explanation:

1) The given parameters are;

The number of student in the class = 21

The median age of the student = 23

The age of the oldest student = 29

Therefore, given that the median age = The age of the (n + 1)/2 th student

Where;

n = The number of student in the class = 21

∴ The median age = The age of the (21 + 1)/2 th = 11 th student, when the age of the students are arranged in increasing order, therefore, we have;

At least one (the 11th) student is 23 (years old), <u>Must be true</u>

2) Given that there are 10 students with ages equal to or lower than the median age, and the difference between the median age and the age of the oldest student = 29 - 23 = 6 years, we have;

Some students are younger than 15 <u>Could be true</u>

5 0

3 years ago

Professors often attempt to determine if the submissions by the students are genuine or copied off the web sources. The program

dlinn [17]

Answer:

0.7385 = 73.85% probability that it is indeed a sample of copied work.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Identified as a copy

Event B: Is a copy

Probability of being identified as a copy:

80% of 15%(copy)

100 - 95 = 5% of 100 - 15 = 85%(not a copy). So

$P(A) = 0.8*0.15 + 0.05*0.85 = 0.1625$

Probability of being identified as a copy and being a copy.

80% of 15%. So

$P(A \cap B) = 0.8*0.15 = 0.12$

What is the probability that it is indeed a sample of copied work?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.12}{0.1625} = 0.7385$

0.7385 = 73.85% probability that it is indeed a sample of copied work.

8 0

3 years ago

Simplify 3 3/4- 1/5

gulaghasi [49]

Answer: 3 11/20

Step-by-step explanation:

You would first simplify 3 3/4 which is 15/4 then you would subtract it with 1/5

Next, you would have to find the GCD ( greatest common factor) for 15/4 and 1/5 which is 20 so multiply 15 by 5 and 4 by 5 which is 75/20, then multiply the top and bottom with 4 for 1/5 which is 4/20 . You then would subtract the simplified forms 75/20 with 4/20 Which is 71/20 which u can simplify to

3 11/20.

7 0

3 years ago

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. how many ways are there to choose:

swat32

Is this a probability question?

7 0

4 years ago

Need your help now please; the assignment is due tonight and this is the last problem I am having trouble with. The red box is t

Kobotan [32]

The volume of the region R bounded by the x-axis is: $\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}$

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

$\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}$

here:

(x₁, y₁) and (x₂, y₂) are two points on the straight line

Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8) from the graph, we have:

$\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}$

y = 4x

Now, our region bounded by the three lines are:

y = 0
x = 2
y = 4x

Similarly, the change in polar coordinates is:

x = rcosθ,
y = rsinθ

where;

x² + y² = r² and dA = rdrdθ

Therefore;

rsinθ = 0 i.e. r = 0 or θ = 0
rcosθ = 2 i.e. r = 2/cosθ
rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)

⇒ r = 0 to r = 2/cosθ
θ = 0 to θ = tan⁻¹ (4)

Then:

$\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}$

$\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}$

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

3 0

2 years ago