Answer:
a = 4
Step-by-step explanation:



hypotenuse = a
opposite = 2√3
adjacent = b
theta = 60°
the best formula to use is the first formula cause we have all the values to substitute in it in order to find the value of a




Answer:

Step-by-step explanation:
To find the average rate of change of a function over a given interval, basically you need to find the slope. The mathematical definition of the slope is very similar to the one we use every day. In mathematics, the slope is the relationship between the vertical and horizontal changes between two points on a surface or a line. In this sense, the slope can be found using the following expression:

So, the average rate of change of:

Over the interval 
Is:


Therefore, the average rate of change of this function over that interval is 3.
Answer:
True kinda. depends on beleif and culture
Step-by-step explanation:
Loga x=n ⇔ a^n=x
log₇ 21=x
x=log ₇ 21
x=ln 21 / ln7=1.564575034...
Answer: x=log₇ 21