Answer:
ihnc
Step-by-step explanation:
ihnc
Answer: ![f'(1)=\dfrac{4}{2y+1}](https://tex.z-dn.net/?f=f%27%281%29%3D%5Cdfrac%7B4%7D%7B2y%2B1%7D)
<u>Step-by-step explanation:</u>
To find the tangent, you need to find the derivative with respect to x.
Then substitute x = 1 into the derivative.
Given: 0 = 2x² - xy - y²
Derivative: 0 = 4x - y' - 2yy'
Solve for y': 2yy' + y' = 4x
y'(2y + 1) = 4x
![y'=\dfrac{4x}{2y+1}](https://tex.z-dn.net/?f=y%27%3D%5Cdfrac%7B4x%7D%7B2y%2B1%7D)
![\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}](https://tex.z-dn.net/?f=%5Ctext%7BSubstitute%20x%20%3D%201%3A%7D%5Cquad%20y%27%281%29%3D%5Cdfrac%7B4%7D%7B2y%2B1%7D)
Answer:
Whats the question? I can surely answer it.
X= number of hours would it take Jason to wash the van by himself.
2x=number of hours would it take Wendy to wash the van by herserlf.
<span>we calcaulate the fraction of work by Jason during one hour </span>
x hours-----------------------------1 work
1 hour---------------------- fraction of work during one hour.
fraction of work during one hour=(1 hour * 1work) / x hours=1/x
we calculate the fraction of work by Wendy during one hour.
2x hours-----------------------------1 work
1 hour---------------------- fraction of work during one hour.
fraction of work during one hour=(1 hour * 1work) / 2x hours=1/2x
We can suggest this equation:
2 hours(fraction of work by Jason during one hour + fraction of work by Wendy during one hour)=1 work
2(1/x + 1/2x)=1
least common multiple=2x
2(2+1)=2x
2(3)=2x
6=2x
x=6/2
x=3
answer: 3 hours would ti take Jason to wash the van by himself.
Answer:
lets call the children, c, and call adult, a,
c+a= 52 eq 1: a=52-c
c=3a eq 2
take a's value from eq 1 and plug it into eq 2
c=3(52-c)
c=156-3c
4c=156
c=39 the number of children that attended the ball game.
Step-by-step explanation: