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timurjin [86]
3 years ago
8

A 25 year old man is 105kg and is 71 inches tall calculate ideal ibw

Mathematics
1 answer:
umka21 [38]3 years ago
6 0

Answer:

IBW  will be 70.8 kg

Step-by-step explanation:

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A blackjack is a 10-point card and an ace for a value of 21. Use your answers to parts (a), (b), and (c) to determine the probab
kondor19780726 [428]

Answer:

Results:

0.1432

0.0045

0.0905

0.0483

Step-by-step explanation:

Step a:

P(A or 10, A or 10) = 20/52 * 19/51 = 5/13 / 19/51 = 95/663 = 0.1432

Step b:

P(A A) = 4/52 * 3/51 = 1/13 * 1/17 = 1/221 = 0.0045

Step c:

P(10 10) = 16/52 * 15/51 = 4/13 * 5/17 = 20/221 = 0.0905

Step d:

P(A 10 or 10 A) = 2 * 4/52 * 16/51 = 2/13 * 16/51 = 32/663 = 0.0483

As well we get the probability by subtracting a,  b and c:  

P(blackjack): 0.1432 - 0.0905 - 0.0045 = 0.0482  

7 0
3 years ago
The graph represents the data cost for monthly internet service for a cell phone. Which function, C(x), respresent the monthly c
Tanya [424]

Answer:

Correct option: first one

Step-by-step explanation:

The graph has 3 different parts:

Cost = 15 when the Gigabytes used is lesser than or equal 2,

Cost from 20 to 40 when the Gigabytes used is greater than 2 and lesser than or equal 6.

An increase of 4 gigabytes caused an increase of 20 in the cost, so the slope is 20/4 = 5, and the y-intercept is:

20 = 5*2 + b -> b = 10

Cost = 50 when the Gigabytes used is greater than 6.

So the correct option is the first one

3 0
3 years ago
Which of the functions below could have created this graph?
bearhunter [10]

Answer:

A

Step-by-step explanation:

Two facts need to guide your answer.

One

The highest power is odd: you know this because an even power would start on the left come down do it's squiggles if had any and wind up on the right going up.

This graph comes down on the left does it's squiggles and then goes further down on the right. That's the behavior of something whose highest power is odd.

Two

The leading coefficient,  the number in front of the highest power must be minus. If it was positive as in y = x^3 the graph would be the mirror image of what it is.

Argument

B and D cannot be true. The highest power is even.

C is false because the leading coefficient is + 1.

So that leave A which is the answer.

The graph is included with this answer

7 0
3 years ago
The first thing to do if your accelerator sticks is to
defon
Answer c. is definitely wrong. I would think b. is the correct answer. if you just just a. shut off the engine you just look control of the vehicle completely.
8 0
3 years ago
Type the correct answer in the box. Use a comma to separate the x- and y-coordinates of each point. The coordinates of the point
MAVERICK [17]

Answer:

On a unit circle, the point that corresponds to an angle of 0^{\circ} is at position (1, \, 0).

The point that corresponds to an angle of 90^{\circ} is at position (0, \, 1).

Step-by-step explanation:

On a cartesian plane, a unit circle is

  • a circle of radius 1,
  • centered at the origin (0, \, 0).

The circle crosses the x- and y-axis at four points:

  • (1, \, 0),
  • (0, \, 1),
  • (-1,\, 0), and
  • (0,\, -1).

Join a point on the circle with the origin using a segment. The "angle" here likely refers to the counter-clockwise angle between the positive x-axis and that segment.

When the angle is equal to 0^\circ, the segment overlaps with the positive x-axis. The point is on both the circle and the positive x-axis. Its coordinates would be (1, \, 0).

To locate the point with a 90^{\circ} angle, rotate the 0^\circ segment counter-clockwise by 90^{\circ}. The segment would land on the positive y-axis. In other words, the 90^{\circ}-point would be at the intersection of the positive y-axis and the circle. Its coordinates would be (0, \, 1).

4 0
3 years ago
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