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Lunna [17]
3 years ago
8

2 x4 + 14x² + x² – 21x – 6 2x² – 3

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
4 0

====== -1-17x-50x^6
=
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Thanks so much for the help!!
saveliy_v [14]

Answer: Domain: x=-2. Range: -2<=y<1

Step-by-step explanation:

Domain: The line is only on one x-point and that is x=-2.

Range: The line is ranging form -2 to 1. However, y=1 is not included on the line but y=-2 is. Hence, the range is notated as -2<=y<1.

3 0
2 years ago
What is the measure of angle K? 102o 118o 134o 156o
stealth61 [152]

Answer:

The measure of angle K is 118°

Step-by-step explanation:

The sum of the internal angles of a quadrilateral is 360°. So, in this case, we can formulate the following equation:

K + L + M + J = 360°

Where K, L, M, and J represent the measure of the angle K, L, M and J respectively.

From the figure we know that: L is 46°, M is 118° and J is 78°. Replacing these values on the initial equation and solving for K we get:

K + 46° + 118° + 78° = 360°

K + 242° = 360°

K = 360° - 242°

K = 118°

So, the measure of angle K is 118°

Hope this helps :)

5 0
3 years ago
Read 2 more answers
The dimensions of a rectangular prism are shown below:
GuDViN [60]

Answer:

...........

Step-by-step explanation:

...........

5 0
3 years ago
Read 2 more answers
The given two-parameter family is a solution of the indicated differential equation on the interval
mr_godi [17]

Answer:

I do 1 option for you as an example, you need to check the leftover by yourself.

Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0

y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)

y(\pi)'=C_1e^\pi cos(\pi)- C_1e^\pi sin(\pi)+ C_2e^\pi sin(\pi) + C_2e^\pi cos (\pi)

Replace C_1 = 0 we have

y'(\pi) = -C_2e^\pi = 0

if and only if C_2 =0

Hence the given solution does not work.

then, d is NOT the correct answer.

3 0
3 years ago
Help with Pre Calculus
marshall27 [118]

Answer:

The first option

Step-by-step explanation:

The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.

So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. x(2x^2-x-15). So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\. So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)}\\\\x=\frac{1\pm\sqrt{1-4(2)(-15)}}{4}\\\\x=\frac{1\pm\sqrt{121)}}{4}\\\\x=\frac{1\pm11}{4}\\\\x=\frac{12}{4}\\x=3\\\\x=\frac{-10}{4}\\x=-\frac{5}{2}

4 0
2 years ago
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