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34kurt
3 years ago
7

A submarine descends 45 1/2 feet from the ocean surface, clinbs 39 ft, and then descends an additional 18 3/4 ft. What must the

submarine now do to reach the ocean surface?
Mathematics
1 answer:
tekilochka [14]3 years ago
7 0
The answer is fill its tanks with air so it floats to the top, but I will solve for the distance since I am nice

so we do
decent means negative
cimb=positive
add

decends 45 and 1/2
-45 and 1/2

climbs 39
+39

decedns 18 and 3/4
-18 and 3/4

add
-45 and 1/2+39-18 and 3/4
add
convert 1/2 to 2/4
gropu negatives
-45 and 2/4-18 and 3/4+39
add
-63 and 5/4+39
-64 and 1/4+39
-25 and 1/4
that is how far dow the submarine is
so the submarine needs to gu 25 and 1/4 ft up to reach the csurface
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Answer:

<em><u>3.5 : 7 > 1.2 : 2.5.</u></em>

Step-by-step explanation:

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Express the given ratios as fraction

5 : 6 = 5/6 and 7 : 9 =7/9

Now find the L.C.M (least common multiple) of 6 and 9

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Making the denominator of each fraction equal to 18, we have

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Now find the L.C.M (least common multiple) of 25 and 2

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