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Ede4ka [16]
3 years ago
14

1. Which statement is false?

Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

Option C is false.

Step-by-step explanation:

A. We are given; 0.7 < 4/5

Now, 4/5 in decimal form is written as 0.8.

Thus,0.7 is less than 0.8. So statement is true.

B) We are given: 2/3 > 0.34

Now, 2/3 in decimal form is written as 0.67.

Thus,0.67 is greater than 0.34, so statement is true.

C) We are given: 2.26 > 214

214 is obviously greater than 2.26. Thus statement is false.

D) We are given: 35/6 > 37/8

Now, 35/6 in decimal form is written as 5.83.

Likewise, 37/8 is written in decimal form as 4.63

Thus,5.83 is greater than 4.63, so statement is true.

Finally, the only false one is Option C

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The product of two rational numbers is irrational.
PtichkaEL [24]

Answer:

The statement is false.

Step-by-step explanation:

Here we need to remember some things:

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An irrational number is a number that can't be written as the quotient of two rational numbers.

Now let's see the statement:

"The product of two rational numbers is irrational."

The product of two rational numbers is written as:

\frac{a}{b} *\frac{c}{d}

Where a, c, b, and d are integers.

We can rewrite that product as:

\frac{a*c}{b*d}

Because of the first property, we know that a*c is an integer, and b*d is also an integer, so here we have a quotient of two integer numbers, so this is a rational number.

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7 0
3 years ago
Show solutions please
slega [8]

Answer:

1. Their ages are:

Steve's age = 18

Anne's age = 8

2. Their ages are:

Max's age = 17

Bert's age = 11

3. Their ages are:

Sury's age = 19

Billy's age = 9

4. Their ages are:

The man's age = 30

His son's age = 10

Step-by-step explanation:

1. We make the assumption that:

S = Steve's age

A = Anne's age

In four years, we are going to have:

S + 4 = (A + 4)2 - 2 = 2A + 8 - 2

S + 4 = 2A + 6 .................. (1)

Three years ago, we had:

S - 3 = (A - 3)3

S - 3 = 3A - 9

S = 3A - 9 + 3

S = 3A – 6 …………. (2)

Substitute S from (2) into (1) and solve for A, we have:

3A – 6 + 4 = 2A + 6

3A – 2A = 6 + 6 – 4

A = 8

Substitute A = 8 into (3), we have:

S = (3 * 8) – 6 = 24 – 6

S = 18

Therefore, we have:

Steve's age = 18

Anne's age = 8.

2. We make the assumption that:

M = Max's age

B = Bert's age

Five years ago, we had:

M - 5 = (B - 5)2

M - 5 = 2B - 10 .......................... (3)

A year from now, it will be:

(M + 1) + (B + 1) = 30

M + 1 + B + 1 = 30

M + B + 2 = 30

M = 30 – 2 – B

M = 28 – B …………………… (4)

Substitute M from (4) into (3) and solve for B, we have:

28 – B – 5 = 2B – 10

28 – 5 + 10 = 2B + B

33 = 3B

B = 33 / 3

B = 11

If we substitute B = 11 into equation (4), we will have:

M = 28 – 11

M = 17

Therefore, their ages are:

Max's age = 17

Bert's age = 11.

3. We make the assumption that:

S = Sury's age

B = Billy's age

Now, we have:

S = B + 10 ................................ (5)

Next year, it will be:

S + 1 = (B + 1)2

S + 1 = 2B + 2 .......................... (6)

Substituting S from equation (5) into equation (6) and solve for B, we will have:

B + 10 + 1 = 2B + 2

10 + 1 – 2 = 2B – B

B = 9

Substituting B = 9 into equation (5), we have:

S = 9 + 10

S = 19

Therefore, their ages are:

Sury's age = 19

Billy's age = 9.

4. We make the assumption that:

M = The man's age

S = His son's age

Therefore, now, we have:

M = 3S ................................... (7)

Five years ago, we had:

M - 5 = (S - 5)5

M - 5 = 5S - 25 ................ (8)

Substituting M = 3S from (7) into (8) and solve for S, we have:

3S - 5 = 5S – 25

3S – 5S = - 25 + 5

-2S = - 20

S = -20 / -2

S = 10

Substituting S = 10 into equation (7), we have:

M = 3 * 10 = 30

Therefore, their ages are:

The man's age = 30

His son's age = 10

3 0
3 years ago
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