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Ede4ka [16]
3 years ago
14

1. Which statement is false?

Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

Option C is false.

Step-by-step explanation:

A. We are given; 0.7 < 4/5

Now, 4/5 in decimal form is written as 0.8.

Thus,0.7 is less than 0.8. So statement is true.

B) We are given: 2/3 > 0.34

Now, 2/3 in decimal form is written as 0.67.

Thus,0.67 is greater than 0.34, so statement is true.

C) We are given: 2.26 > 214

214 is obviously greater than 2.26. Thus statement is false.

D) We are given: 35/6 > 37/8

Now, 35/6 in decimal form is written as 5.83.

Likewise, 37/8 is written in decimal form as 4.63

Thus,5.83 is greater than 4.63, so statement is true.

Finally, the only false one is Option C

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GaryK [48]

1. The given rectangular equation is x=2.

We substitute x=r\cos \theta.

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Divide through by \cos \theta

r=\frac{2}{\cos \theta}

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\boxed{x=2\to r=2\sec \theta}

2. The given rectangular equation is:

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x^2+y^2=6^2

We use the relation r^2=x^2+y^2

This implies that:

r^2=6^2

\therefore r=6

\boxed{x^2+y^2=36\to r=6}

3. The given rectangular equation is:

x^2+y^2=2y

This is the same as:

We use the relation r^2=x^2+y^2 and y=r\sin \theta

This implies that:

r^2=2r\sin \theta

Divide through by r

r=2\sin \theta

\boxed{x^2+y^2=2y\to r=2\sin \theta}

4. We have x=\sqrt{3}y

We substitute y=r\sin \theta and x=r\cos \theta

r\cos \theta=r\sin \theta\sqrt{3}

This implies that;

\tan \theta=\frac{\sqrt{3}}{3}

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r\cos \theta=r\sin \theta

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If ANGL is a square, then NG and LG are adjacent sides.

Adjacent sides are perpendicular.  [Each angle is 90°]

The equation of line NG is Y=\dfrac12 X-6.

By comparing it to equation in slope intercept form y=mx+c ( where , m= slope , c=y-interecpt)

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