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Anton [14]
3 years ago
8

X = 53. What is the value of x ?

Mathematics
1 answer:
kompoz [17]3 years ago
7 0
53



20 words do b annoying
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-1

because you are adding up to 0 to get back to the positive.

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The table below represents the closing cost of ABC for the last 5 days. What is the r -value of the linear regression that fits
Gnoma [55]

Answer:

The correct option is D.

Step-by-step explanation:

The linear regression equation is in the form of

y=bx+a

Where,

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}

The formula of r is

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n(\sum x^2)-(\sum x)^2][n(\sum y^2)-(\sum y)^2]}}

The values are

\sum x=15,\sum y=98.91,\sum x^2=55,\sum y^2=1957.8295,\sum xy=293.78, n=5

Using above formula, we get

r=-0.85650

Therefore option D is correct.

3 0
3 years ago
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Under a certain transformation T, AA'BC' is the image of AABC. The perimeter of AA'B'C' is twice the perimeter of ABC. What kind
Anika [276]

The dimensions of the image are twice the dimensions of the preimage,

which indicates that the transformation is a dilation.

  • The transformation <em>T</em> is; <u>a dilation transformation with a scale factor of 2, D₂</u>

Reasons:

The transformation applied to ΔABC = T

The image of ΔABC following the transformation, T = ΔA'B'C'

The perimeter of ΔA'B'C' = Twice the perimeter of ΔABC

Therefore, we have;

A'B' + B'C' + A'C' = 2 × (AB + BC + AC)

Which gives

A'B' + B'C' + A'C' = 2·AB + 2·BC + 2·AC

By similar triangles, we have the ratio of corresponding sides as follows;

\displaystyle \frac{AB}{A'B'}  = \frac{BC}{B'C'} = \mathbf{ \frac{AC}{A'C'}}

Which gives;

\displaystyle \frac{AB}{A'B'}  = \frac{AB}{2 \cdot AB} = \frac{1}{2}

A'B' = 2·AB

Therefore;

  • Triangle ΔA'B'C' is twice the dimension of triangle ΔABC, and <em>T</em> is <u>a dilation transformation with a scale factor of 2, D₂</u>

Learn more about dilation transformation here:

brainly.com/question/2458912

3 0
2 years ago
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