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ki77a [65]
2 years ago
13

What is the coordinate of point A?

Mathematics
2 answers:
goldenfox [79]2 years ago
7 0

34.25 is the correct answer

nirvana33 [79]2 years ago
5 0

There are 4 spaces between 34 and 35. This means each line is 1/4

A is located at 34.25

You might be interested in
Which property would allow you to use mental computation to simplify the problem 27 + 15 + 3 + 5? additive identity additive inv
Fofino [41]

Answer:

Commutative Property

Step-by-step explanation:

Additive Identity: If you add a real number to zero or add zero to a real number, then you get the same real number back.

Additive Inverse: When you add the same number but reversed sign, you get 0.

Commutative Property: a + b = b + a

Addition distributive property: a(b+ c) = ab + ac.

In this case, we use the commutative property:

27 + 15 + 3 + 5 = 27 + 3 + 15 + 5.

We know that 27 + 3 = 30 and 15 + 5 = 20, so we get 50 quickly using mental math.

5 0
3 years ago
Read 2 more answers
(n/‒7) + 3 = ‒2<br> explain it
iris [78.8K]

Answer:

The answers is n=35

Step-by-step explanation:

Solve for n by simplifying both sides of the equation. Then isolating the variable.

J’espère que ça aide.

5 0
3 years ago
Read 2 more answers
What is the ratio 18 to 27 written as a fraction in lowest terms?
Studentka2010 [4]
18:27=\dfrac{18}{27}=\dfrac{18:9}{27:9}=\dfrac{2}{3}=2:3
7 0
3 years ago
New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.
elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0
3 years ago
2x + y - z = -8
Andreyy89

Answer:

Multiply row 1 by \frac{1}{2}.

Step-by-step explanation:

The augmented matrix of the system of linear equation is described below:

\left[\begin{array}{cccc}2&1&-1&-8\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]

Where a_{11} = 2, if we need to create a_{11} = 1, we need to multiply row 1 by \frac{1}{2}, that is to say:

\left[\begin{array}{cccc}1&\frac{1}{2} &-\frac{1}{2} &-4\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]

Hence, the correct answer is: Multiply row 1 by \frac{1}{2}.

5 0
3 years ago
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