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lora16 [44]
2 years ago
6

In order to average together values that match two different conditions in different ranges, an Excel user should use the functi

on.
Computers and Technology
1 answer:
Tomtit [17]2 years ago
6 0
In order to average together values that match two different conditions in different ranges, an Excel user should use the Excel Average functions.<span>To calculate average in Excel,the powerful Excel Average functions will do the work behind the scene.  </span>You use the AVERAGE function in Excel to return the average (arithmetic mean) of the specified cells. The different functions are : <span><span>Excel AVERAGE - calculate the mean of cells with numbers.  </span><span>Excel AVERAGEA - find an average of cells with any data. </span><span>Excel AVERAGEIF - average cells based on a given criterion. </span><span>Excel AVERAGEIFS - average cells that match several criteria.</span></span>
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Write the code for invoking a method named sendObject. There is one argument for this method which is of type Customer. Assume t
kodGreya [7K]

Answer:

sendObject(John_Doe);

Explanation:

The above code has been written in Java.

Since the calling class is the same that declares it, to invoke the method, simply call its name with its argument(s) in a pair parentheses. The name of the method is "sendObject" and its argument is a reference to an object of type Customer saved in a variable called "John_Doe". This can be written as follows:

sendObject(John_Doe);

Hope this helps!

3 0
3 years ago
Use the drop-down tool to match each definition to the correct word or phrase. The computer that responds to requests from the c
Lera25 [3.4K]

Answer:

The computer that responds to requests from the client computer:  

Server

Connects network devices or different parts of a network:  

Switch

A piece of equipment that directs data where it should go:  

Router

Connects many different Ethernet devices and allows them to connect to the network with one connection:  

Hub

The computer that uses service provided by a server:  

Client

Explanation:

6 0
2 years ago
What technical was the microscope invented in?
Ilia_Sergeevich [38]

Answer:

Two Dutch spectacle-makers and father-and-son team, Hans and Zacharias Janssen, create the first microscope in 1590.

Explanation:

A microscope is an instrument that makes an enlarged image of a small object, thus revealing details too small to be seen by the unaided eye. The most familiar kind of microscope is the optical microscope, which uses visible light focused through lenses. Eeuwenhoek observed animal and plant tissue, human sperm and blood cells, minerals, fossils, and many other things that had never been seen before on a microscopic scale. He presented his findings to the Royal Society in London, where Robert Hooke was also making remarkable discoveries with a microscope.

8 0
2 years ago
a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv
Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that  cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// chracter to digit mapping, and the inverse</em>

<em>// (if you want better performance: use array instead of unordered_map)</em>

<em>unordered_map<char, int> c2i;</em>

<em>unordered_map<int, char> i2c;</em>

<em>int ans = 0;</em>

<em>// limit: length of result</em>

<em>int limit = 0;</em>

<em>// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]  </em>

<em>bool helper(vector<string>& words, string& result, int digit, int widx, int sum) { </em>

<em>    if (digit == limit) {</em>

<em>        ans += (sum == 0);</em>

<em>        return sum == 0;</em>

<em>    }</em>

<em>    // if summation at digit position complete, validate it with result[digit].</em>

<em>    if (widx == words.size()) {</em>

<em>        if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {</em>

<em>            if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result</em>

<em>                return false;</em>

<em>            c2i[result[digit]] = sum % 10;</em>

<em>            i2c[sum%10] = result[digit];</em>

<em>            bool tmp = helper(words, result, digit+1, 0, sum/10);</em>

<em>            c2i.erase(result[digit]);</em>

<em>            i2c.erase(sum%10);</em>

<em>            ans += tmp;</em>

<em>            return tmp;</em>

<em>        } else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){</em>

<em>            if (digit + 1 == limit && 0 == c2i[result[digit]]) {</em>

<em>                return false;</em>

<em>            }</em>

<em>            return helper(words, result, digit+1, 0, sum/10);</em>

<em>        } else {</em>

<em>            return false;</em>

<em>        }</em>

<em>    }</em>

<em>    // if word[widx] length less than digit, ignore and go to next word</em>

<em>    if (digit >= words[widx].length()) {</em>

<em>        return helper(words, result, digit, widx+1, sum);</em>

<em>    }</em>

<em>    // if word[widx][digit] already mapped to a value</em>

<em>    if (c2i.count(words[widx][digit])) {</em>

<em>        if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0) </em>

<em>            return false;</em>

<em>        return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);</em>

<em>    }</em>

<em>    // if word[widx][digit] not mapped to a value yet</em>

<em>    for (int i = 0; i < 10; i++) {</em>

<em>        if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;</em>

<em>        if (i2c.count(i)) continue;</em>

<em>        c2i[words[widx][digit]] = i;</em>

<em>        i2c[i] = words[widx][digit];</em>

<em>        bool tmp = helper(words, result, digit, widx+1, sum+i);</em>

<em>        c2i.erase(words[widx][digit]);</em>

<em>        i2c.erase(i);</em>

<em>    }</em>

<em>    return false;</em>

<em>}</em>

<em>void isSolvable(vector<string>& words, string result) {</em>

<em>    limit = result.length();</em>

<em>    for (auto &w: words) </em>

<em>        if (w.length() > limit) </em>

<em>            return;</em>

<em>    for (auto&w:words) </em>

<em>        reverse(w.begin(), w.end());</em>

<em>    reverse(result.begin(), result.end());</em>

<em>    int aa = helper(words, result, 0, 0, 0);</em>

<em>}</em>

<em />

<em>int main()</em>

<em>{</em>

<em>    ans = 0;</em>

<em>    vector<string> words={"GREEN" , "BLUE"} ;</em>

<em>    string result = "BLACK";</em>

<em>    isSolvable(words, result);</em>

<em>    cout << ans << "\n";</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0
2 years ago
The benefits of a career as compared to a job include all of the following except
Digiron [165]

C and D are direct opposite so one of them cannot be true. A career will bring more responsibilities. So the answer is D. less responsibilities.

6 0
3 years ago
Read 2 more answers
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