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Dmitry [639]
3 years ago
14

Write the code for invoking a method named sendObject. There is one argument for this method which is of type Customer. Assume t

hat there is a reference to an object of type Customer, in a variable called John_Doe. Use this reference as your argument. Assume that sendObject is defined in the same class that calls it.
Computers and Technology
1 answer:
kodGreya [7K]3 years ago
3 0

Answer:

sendObject(John_Doe);

Explanation:

The above code has been written in Java.

Since the calling class is the same that declares it, to invoke the method, simply call its name with its argument(s) in a pair parentheses. The name of the method is "sendObject" and its argument is a reference to an object of type Customer saved in a variable called "John_Doe". This can be written as follows:

sendObject(John_Doe);

Hope this helps!

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Select the correct answer from each drop-down menu. Which IF formulas are valid? _____ and _____ are valid IF formulas.
Lyrx [107]

Answer:

=IF(D3>50; E3; F3) AND =IF(A1>60;"Pass";"Fail")

Explanation:

An IF structure is built following this pattern:

IF(TEST;IFTRUE;IFFALSE)

These are the only options in the given drop-down menus what comply with this pattern.  All others are not following this pattern.

The computer will do the test and if the result is true will apply the IFTRUE value, otherwise will apply the IFFALSE value.

4 0
3 years ago
QUESTION
Lady_Fox [76]

Answer:

Explanation:

#include <iostream>

using namespace std;

int main ()

{

   int responses[30],count[6];

   int score = 0;

   string resp = " ";

   for (int i = 0; i < 30; i++)

   {

    responses[i] = 0;

   }

   for (int i = 0; i < 6; i++)

   {

    count[i,1]=0;

    count[i,2]=0;

    count[i,0]=0;

   }

   while ((resp != "Y") && (resp != "y"))

   {

    for (int i = 0; i < 30; i++)

    {

        while ((score > 5) || (score < 1))

           {

            cout << "Student " << (i+1)<< " please enter a value (1-5):";

            cin >> score;

        }

           responses[i] = score;

           if((score > 5)||(score<1))

           {

               if(score==1) count[1]++;        

               if(score==2) count[2]++;        

               if(score==3) count[3]++;        

               if(score==4) count[4]++;        

               if(score==5) count[5]++;        

           }

           score = 0;

    }

    cout<< "Response               Frequency              Percentage"<<endl;;

    cout<< "    1                      "<<count[1]<<"               "<<(count[1]/30)<<"%"<<endl;

    cout<< "    2                      "<<count[2]<<"               "<<(count[2]/30)<<"%"<<endl;

    cout<< "    3                      "<<count[3]<<"               "<<(count[3]/30)<<"%"<<endl;

    cout<< "    4                      "<<count[4]<<"               "<<(count[4]/30)<<"%"<<endl;

    cout<< "    5                      "<<count[5]<<"               "<<(count[5]/30)<<"%"<<endl;

    cout<< "Do you want to exit? Press Y to exit any other key to continue: ";

    cin>> resp;

   }

   return 0;

}

8 0
3 years ago
Which of the following is NOT an example of a font style?
erastovalidia [21]
C. Underline because it is not a kind of font. it is an effect.
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erma4kov [3.2K]

Answer:

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